## anonymous 3 years ago help?!?

1. Luigi0210

@Jhannybean

2. Luigi0210

I have never gotten to series in calculus Lala, sorry.. but I called someone better for you :)

3. anonymous

In a geometric series, the series will converge if $\large |r|<1$In this case, $|-\frac{1}{2}| <1 \implies \frac{1}{2}< 1$ therefore the $\large \sum_{n-1}^{\infty}-4(-\frac{1}{2})^{n-1} = C$

4. anonymous

thank you @Luigi0210

5. anonymous

Because it converges, your sum : $\large S=\frac{a}{1-r}$ where $\large r=-\frac{1}{2}$

6. Luigi0210

that stuff looks so familiar >.<

7. anonymous

TRue that

8. anonymous

so that is the answer?

9. anonymous

yes

10. anonymous

oh ok!

11. anonymous

thanks

12. anonymous

you think you could help with another?