Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.2
@Jhannybean
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.2
I have never gotten to series in calculus Lala, sorry.. but I called someone better for you :)
 one year ago

Jhannybean Group TitleBest ResponseYou've already chosen the best response.3
In a geometric series, the series will converge if \[\large r<1\]In this case, \[\frac{1}{2} <1 \implies \frac{1}{2}< 1\] therefore the \[\large \sum_{n1}^{\infty}4(\frac{1}{2})^{n1} = C\]
 one year ago

lala2 Group TitleBest ResponseYou've already chosen the best response.0
thank you @Luigi0210
 one year ago

Jhannybean Group TitleBest ResponseYou've already chosen the best response.3
Because it converges, your sum : \[\large S=\frac{a}{1r}\] where \[\large r=\frac{1}{2}\]
 one year ago

Luigi0210 Group TitleBest ResponseYou've already chosen the best response.2
that stuff looks so familiar >.<
 one year ago

carlton123 Group TitleBest ResponseYou've already chosen the best response.0
TRue that
 one year ago

lala2 Group TitleBest ResponseYou've already chosen the best response.0
so that is the answer?
 one year ago

lala2 Group TitleBest ResponseYou've already chosen the best response.0
you think you could help with another?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.