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Luigi0210
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@Jhannybean
Luigi0210
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I have never gotten to series in calculus Lala, sorry.. but I called someone better for you :)
Jhannybean
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In a geometric series, the series will converge if \[\large |r|<1\]In this case, \[|-\frac{1}{2}| <1 \implies \frac{1}{2}< 1\] therefore the \[\large \sum_{n-1}^{\infty}-4(-\frac{1}{2})^{n-1} = C\]
lala2
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thank you @Luigi0210
Jhannybean
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Because it converges, your sum : \[\large S=\frac{a}{1-r}\] where \[\large r=-\frac{1}{2}\]
Luigi0210
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that stuff looks so familiar >.<
carlton123
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TRue that
lala2
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so that is the answer?
carlton123
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yes
lala2
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oh ok!
lala2
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thanks
lala2
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you think you could help with another?