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with what

this is it

can anyone help?

So, for the first term, "x^5" term, you have:
(5C0)[(2x)^5][(-3y)^0]
(1)(32x^5)(1)
32x^5

so you have to keep going?

Of course! In my first post, you should have read that there are 5 "+" signs, giving 6 total terms.

oh!

ok give me some time to do them.. could you check them when im done?

sure, np!

sixth is
-1215y^5

I just punched it into the calc

To start, what's 5C2 ?

oh

so 720 (x^3)(y^2)

Yes, that is the correct 3rd term.

ok!

for the fourth what is the (5c3) and (5c5)

ok

hello?

is 6th term -2430 (y^5)

For the 6th term:
(5C5)[(2x)^0][(-3y)^5] =
(1)(1)(-243y^5) =
-243y^5 =
-243(y^5)

oh ok! I need some practice lol!

thank you!

uw!

thanks!