## lala2 2 years ago help?

yes

3. lala2

@tcarroll010

4. lala2

think you can help?

5. tcarroll010

Since you want to consider 2 consecutive EVEN integers, you conceive of the first one as: 2x and the next one as 2x + 2 The multiplier of 2 guarantees that it will be even: 1/(2x) + 1/(2x + 2) = 9/40

6. tcarroll010

1/x + 1/(x + 1) = 9/20 [(x + 1) + x] / [x(x + 1)] = 9/20 40x + 20 = 9x^2 + 9x 9x^2 - 31x - 20 = 0 x = 4 -> so 2x = 8 and the next # is 10 1/8 + 1/10 = 9/40

7. lala2

im kinda confused as to what ll of this means

8. lala2

*all

9. tcarroll010

You're looking for 2 consecutive even numbers such that 1 over the first number plus 1 over the second number = 9/40 Those 2 numbers are 8 and 10 because: 1/8 + 1/10 = 9/40 And the equation is set up with the first number being represented as: 2x and the second # is then 2x + 2 The "2" will guarantee that your eventual numbers are even. So you start with that, go to the equation I set up, and solve for "x". Then you take 2x for the first # and 2x + 2 for the second #.

10. tcarroll010

You don't have to find anything. The problem is started and finished. The first number is 8 and the second number is 10.

11. tcarroll010

The reciprocal of 8 is 1/8 The reciprocal of 10 is 1/10 1/8 + 1/10 = 9/40 The 2 numbers that answer the question are 8 and 10.

12. tcarroll010

I hope that you are finding that this is making sense because the problem is done and the explanation is given in detail. All good now, @lala2 ?

13. tcarroll010

Well, the answer is in 2 parts. You need the initial equation and then you need: 8 and 10.

14. tcarroll010

uw!

15. tcarroll010

Actually, the equation is: 1/(2x) + 1/(2x + 2) = 9/40

16. tcarroll010

The problem is asking for an equation than can be used to find the 2 numbers. So, the equation has to have a variable in it.

17. lala2

oh ok!

18. tcarroll010

I suggest you go over all the logic here. It might help.

19. lala2

yeah that's what im doing!

20. tcarroll010

ok, well thx for the recognition and have a great day.