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rachelgarisue13
What is the exact value of 3q^8/ sqrt q^19? Simplify if possible.
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\[\frac{3q^8}{\sqrt{q^{19}}}\] Remember that \(\sqrt{x}\) can be written as \(x^{1/2}\) and that \((x^n)^m = x^{n*m}\) After using that to simplify the denominator, remember that \[\frac{x^a}{x^b} = x^{a-b}\]
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