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Where are you stuck? If you are wondering how to start, you want to divide out your leading coefficient on your x^2 term.
you subtract 24 from both side, to zero out the equation, then you use the square this to solve
okay i did the (b/2)^2 thing and then got 3x^2 - 6x +9 = 33. then i divided the 3 which resulted to 3(x^2-2x+3)=33 now i cant factor that, i think i did something wrong, i just dont know what it is
|dw:1370393983063:dw| just factor this out
You need to first divide out the leading coefficient \(3x^2-6x=24 \rightarrow x^2-2x=8\) Then take half of your second term, square it and then add that to both sides.
@eSpeX no they need to zero out the equation and then factor it
@thefukintoilet there is if you are following the instructions to "complete the square" in order to solve the equation.
oh ok im sorry @eSpeX
No worries, you never know where the student is in their lesson so I always try to adhere to the instructions offered.
Once you divide 3 out of every term in the equation it is gone and you no longer have to worry about it.
ohhhh okay thankss
You're welcome, do you know how to finish this problem then?
i got 10
hmm, I got 4, can you show me how you got your answer?
3x^2-6x=24 x^2-2x=8 (-2/2) = -1^2 = 1 x^2-2x+1=8+1 (x-1)(x-1)=9 x-1=9 +1=+1 x=10
You need to add a step. After (x-1)(x-1)=9, you should have \((x-1)^2=9\) Then take the sqrt of both sides and solve for 'x'.
ohhh got it.
now i got 4, thaaank you so much.
You are welcome.