anonymous
  • anonymous
Identify the center of the circle whose equation is (x - 2)² + (y + 8)² = 16.
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
PLEASE HELP HAVE TO HAVE THIS TEST TURNED IN BY 12AM
Mertsj
  • Mertsj
Do I understand that you are cheating on a test?
anonymous
  • anonymous
No i didnt ask for the answer i need help learning how to solve it like an example

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Mertsj
  • Mertsj
\[(x-h)^2+(y-k)^2 = r^2 \]
Mertsj
  • Mertsj
Equation of a circle. Center (h,k) radius = r
anonymous
  • anonymous
ok so do i use the that equation
anonymous
  • anonymous
i need some help totaly confused
whpalmer4
  • whpalmer4
@Mertsj has given you the formula and description. Now you have to match up your equation with the formula, and interpret it.
whpalmer4
  • whpalmer4
Look at the first term: \((x-2)^2\) Compare with the formula: \((x-h)^2\) where \(h\) is the \(x\)-coordinate of the center of the circle. Any ideas?
whpalmer4
  • whpalmer4
Do the same with \(y\) and \(r\) terms. Note that the \(y\) term has a + in it instead of a - sign. How do you subtract, yet end up adding?
anonymous
  • anonymous
This original equation is (x-#) +(y-#)=radius The center is (2, -8) because when you plug in -8, negative plus a negative equals a positive. 2stays the same because you just plug in the number#
anonymous
  • anonymous
Ohhhhhhhhhhh ok
anonymous
  • anonymous
thank yall so much for explaing it

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