anonymous
  • anonymous
help with 3 questions about triangles?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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reemii
  • reemii
sure?
anonymous
  • anonymous
anonymous
  • anonymous
please help!

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reemii
  • reemii
you need to remember two things for triangles: 1) cos(a) = (adjacent) / (hypothenuse) (->then sin(a) = (opposite)/(hypothenuse)) 2) tan(a) = sin(a)/cos(a) |dw:1370408887356:dw| tan(a) = sin a /cos a = opposite / adjacent = 12/16 right?
reemii
  • reemii
i mean tan("x") = 12/16..
anonymous
  • anonymous
yeah 3/4
reemii
  • reemii
sure, and the second one is quite immediate too. what do you get?
reemii
  • reemii
straightforward*
anonymous
  • anonymous
i just dont know how to do these lol...
reemii
  • reemii
sin(x) = opposite / hypothenuse
reemii
  • reemii
write the fraction, and simplify
anonymous
  • anonymous
30/34= 15/17?
reemii
  • reemii
why 30?
reemii
  • reemii
it's the opposite to the angle x, so it's 16/34
anonymous
  • anonymous
and the last one? how do i figure that one out
reemii
  • reemii
now you know x, x = 63°. They say "use the cosine". The formula is cos(63) = adj / hyp right? It turns out that in this equation, only "hyp" is unknown. Therefore you just have to isolate it.
anonymous
  • anonymous
so how do i figure it out?
reemii
  • reemii
53*
reemii
  • reemii
write the equation for the cosine: \(\cos(53) = \frac{7}{H}\). -> \(H = \dots\). use a calculator to compute cos(53°) and you're done.
anonymous
  • anonymous
my answer is coming out to be .6
reemii
  • reemii
for the cos(53) ? yes. then, what is H?
anonymous
  • anonymous
9.29
reemii
  • reemii
what formula did you use?
reemii
  • reemii
\[\cos(53°) = \frac7H\\ \iff H = \frac{7}{cos(53°)} = \frac7{0.602} = \dots\]
anonymous
  • anonymous
9.29?
reemii
  • reemii
It's not that hard: if you don't have a calculator, you can use google. it'll tell you "7/0.602 = 11.6279069767 = 11.63" more or less
reemii
  • reemii
@ogkat it's done.

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