anonymous
  • anonymous
What is the sum of a 6-term geometric series if the first term is 20 and the last term is 336,140?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ganeshie8
  • ganeshie8
try finding the common ratio r, then use series formula
anonymous
  • anonymous
how do you find the common ratio?
ganeshie8
  • ganeshie8
\(a = 20\) \(t_n = ar^{n-1}\)

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ganeshie8
  • ganeshie8
6th term = 336,140 \( t_6 = ar^{6-1}\) \( 336140 = 20r^{5}\)
ganeshie8
  • ganeshie8
you can find r ?
anonymous
  • anonymous
To find r, do we divide that big number by 20?
ganeshie8
  • ganeshie8
yes
ganeshie8
  • ganeshie8
\(\frac{336140}{20} = r^{5}\)
ganeshie8
  • ganeshie8
you may use your calculator
anonymous
  • anonymous
so it would be 20 1-16807^6/1-16807?
ganeshie8
  • ganeshie8
close ! but the r you got is incorrect !
ganeshie8
  • ganeshie8
\(\frac{336140}{20} = r^{5}\)\(\) \(16807 = r^5\) \(7^5 = r^5\) \(7 = r\)
ganeshie8
  • ganeshie8
plugin r = 7, in the series formula and find the sum...
anonymous
  • anonymous
How did you get 7^5 from 16807?
ganeshie8
  • ganeshie8
16807 = 7x7x7x7x7 = 7^5 ive used my calculator
anonymous
  • anonymous
thank you!
ganeshie8
  • ganeshie8
np :)

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