anonymous
  • anonymous
Problem,
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1370428391186:dw| Open circuit,
anonymous
  • anonymous
|dw:1370428508799:dw| Magnet passes through the coil, if the circuit was closed current will flow thus creating a magnetic field that opposes the magnet. But because the circuit is a opened circuit,current can not flow, thus the magnet moves freely feeling no Lenz's effect, so lenz's law is not applied here because I = 0 So B of coil = 0.
anonymous
  • anonymous
|dw:1370428672204:dw| Copper pipe, similarly like a loop of wire, it has a "path" for current to flow in, thus there is a magnetic field opposing the magnet passing the copper pipe.

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anonymous
  • anonymous
|dw:1370428760981:dw|
anonymous
  • anonymous
@experimentX
anonymous
  • anonymous
thats my point :)
anonymous
  • anonymous
I found my answer here: http://www.youtube.com/watch?v=OJvEOXsSuaQ
anonymous
  • anonymous
|dw:1370429717955:dw| I guess the whole point of this, is that in order for current to flow the path has to be closed.
anonymous
  • anonymous
current flows here: |dw:1370429803621:dw| current does not flow in here: |dw:1370429893874:dw|
anonymous
  • anonymous
|dw:1370430501749:dw|

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