anonymous
  • anonymous
(3d^2+2d-29) ÷ (d+3)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@Hero :D
anonymous
  • anonymous
Okay, so: (3d^2+1d^2-29) ...the 29 doesn't factor...
Hero
  • Hero
Now you're changing it. First it was 3d^2 + 2d - 29

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anonymous
  • anonymous
I though factoring was: Heres an example: example: given \[y^2-4\] this could be rewritten as: \[y^2-2^2\] and using the fact i gave for factorising difference of two squares, \[(y+2)(y-2)\]
anonymous
  • anonymous
Hmm?
Hero
  • Hero
That's difference of squares. It's one of several factoring methods. There's no difference of squares in this particular expression.
Hero
  • Hero
If you can't factor, then just use long division
anonymous
  • anonymous
Oh, ok. So what do I do then? Oh...you just said...
anonymous
  • anonymous
\[3d ^{2}+2d-29\div(d+3)\]
Hero
  • Hero
You need to do long division for this bro
anonymous
  • anonymous
Ok so like: ...Could you help or give an example?
Hero
  • Hero
It's impossible to do long division on this site...without giving answers so, I'll direct you to a resource: http://calc101.com/webMathematica/long-divide.jsp
anonymous
  • anonymous
Oh cool...this shows you all the work thanks :D your my @Hero lol

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