anonymous
  • anonymous
Plot points A(-3,2) B(4,2) C(2,-3) and D(-5,-3) Find its area and perimeter. PLS HELP ME
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
i find it might make things simpler by "moving" this so that one of the points is at the origin; helps me to see the the shapes better
anonymous
  • anonymous
Plot the points according to your knowledge of coordinate system and then detect what figure is that whether it is square, rectangle or some other one.
anonymous
  • anonymous
Use distance formula for calculating side's distances

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anonymous
  • anonymous
ITS A PARALLELOGRAM
amistre64
  • amistre64
since it feels to me that -5,-3 is the farthest away, ill adjust all the points by that A(-3,2) B(4,2) C(2,-3) D(-5,-3) 5 3 5 3 5 3 5 3 ------------------------------ 2 5 9 5 7 0 0 0
anonymous
  • anonymous
If it is a parellelogram then use the formula for finding area of it : base * corresponding height.
anonymous
  • anonymous
what is the base and height? pls help :(
anonymous
  • anonymous
Take any side as base and then decide the corresponding height. Wait lemme draw a diagram.
amistre64
  • amistre64
A(-3,2) B(4,2) C(2,-3) D(-5,-3) 5 3 5 3 5 3 5 3 ------------------------------ 2 5 9 5 7 0 0 0 ^________^ ^-------^ 5 high 7 wide
anonymous
  • anonymous
ok :) thanks for the hep :)
amistre64
  • amistre64
A(-3,2) 5 3 ----- 2 5 ^^^^ this is our offset, so that the slant length can be determined using pythag
anonymous
  • anonymous
|dw:1370436249151:dw||dw:1370436316532:dw|
anonymous
  • anonymous
thanks for all the help :)
anonymous
  • anonymous
(It depends what side you consider as base ) --- Amistre is explaining well. Follow him :)
anonymous
  • anonymous
uhm, I can't understand it very well, how can I find out the base and the height if there are coordinates?
amistre64
  • amistre64
2 5 9 5 0 0 7 0 a skewed rectangle retains the same area|dw:1370436472416:dw|
amistre64
  • amistre64
the base and height can be better seen by positioning this thing at the origin ... at least thats the simplest way i can see it
amistre64
  • amistre64
the corrdinants given correspond to: 2 5 9 5 ||height is from 0 to 5 0 0 7 0 ------- base is from 0 to 7
amistre64
  • amistre64
bad formatted lol 2 5 / / the slanted side has a length of a 2,5 rt triangle 0 0 / to fiinsh with the perimete
amistre64
  • amistre64
we already have enough information for the area, can you tell me what you think it would be?
anonymous
  • anonymous
10? i really don't know im just in middle school :(
amistre64
  • amistre64
the area corresponds to the "rectangle" of the same proportions. do you recall how to find the area of a rectangle?
anonymous
  • anonymous
W X H
amistre64
  • amistre64
correct, since the width is 7 and the hieght is 5 .... we can determine the area
anonymous
  • anonymous
35? :) but how did youu know that 7 is the width and 5 the height?
anonymous
  • anonymous
This will help .
1 Attachment
amistre64
  • amistre64
it was easily determined after i "moved" it to the origin; all i needed to do was measure the height and width from the origin
amistre64
  • amistre64
|dw:1370437197893:dw|
anonymous
  • anonymous
I GET IT :) THANK YOU VERY MUCH :) BUT HOW ABOUT THE PERIMETER?
anonymous
  • anonymous
PFA
1 Attachment
anonymous
  • anonymous
Add all the sides' distances to find the perimeter.
amistre64
  • amistre64
well, we already know 2 sides .. top and bottom are 7 we simply need to determine the slanted length
amistre64
  • amistre64
|dw:1370437317944:dw|
amistre64
  • amistre64
how do you find the length of that part of a rt triangle if you know the legs?
amistre64
  • amistre64
....kept trying to call it a hypothesis :) its the hypotenuse thing pythag thrm
anonymous
  • anonymous
uhm, i'll try :)
anonymous
  • anonymous
29?
amistre64
  • amistre64
|dw:1370437515909:dw|
amistre64
  • amistre64
29 is part of it, but you have to sqrt it
anonymous
  • anonymous
it doesnt have a sqr rt
amistre64
  • amistre64
\[n^2 = 5^2 + 2^2\] \[n^2 = 25 + 4\] \[n^2 = 29\] \[n = \sqrt{29}\]
anonymous
  • anonymous
ahhh :)
anonymous
  • anonymous
what will happen next?
amistre64
  • amistre64
and we have 2 of those parts giving us:\[7+7+\sqrt{29}+\sqrt{29}\] \[14+2\sqrt{29}\] as a perimeter, its up to you to determine of you want an exact result or an approximation
anonymous
  • anonymous
what is the exact result o.O?
amistre64
  • amistre64
that IS the exact result ... an approximation would have a single decimal expansion as a value.
amistre64
  • amistre64
sqrt(29) is approximately 5.4 14 + 2(5.4) 14 + 10.8 = 24.8 as an approximation
anonymous
  • anonymous
THANK YOU VERY MUCH <3 can you please help me with this problem? Plot the points M(-2,5) N(4,5) 0(7,1) P (-5,1) A.Find its area and perimeter B. How long is the median xy of MNOP?
amistre64
  • amistre64
i cant at the moment, but post it as a new question to the left and someone is bound to help you out :) i have a paying job that i have to attend to at the moment.
amistre64
  • amistre64
but as a hint, i see the -5 might be the lowest point, so id move it all and set P at the origin
anonymous
  • anonymous
oh sorry my bad :( but tanks for the help I really appreciate it :)
amistre64
  • amistre64
good luck
anonymous
  • anonymous
My solution : You have four points : A(-3,2) B(4,2) C(2,-3) and D(-5,-3) \[\left.\begin{array}{c}A(-3,2)\\B(4,2)\\C(2,-3)\\D(-5,3)\end{array}\right ]\textbf{Given}\] [Please check the attachment - Faye1 for the graph of these points ] Calculate AB, BC , CD and AD (4 sides of the quadrilateral ABCD ) (Formula used : Distance Formula \(\rightarrow\) : Distance between any two points : \(\large{(x_1,y_1)}\) and \(\large{(x_2,y_2)}\) is \[\large{\sqrt{(x_2 - x_1 )^2 + (y_2 - y_1)^2 } } \] So using this formula for calculating AB, BC , CD and AD : AB : \(\large{\sqrt{7^2 + 0^2 } = \sqrt{7^2} = 7}\) BC : \(\large{\sqrt{(2-4)^2 + (-3-2)^2 } = \sqrt{(-2)^2 + (-5)^2} = \sqrt{4 + 25} = \sqrt{29} }\) CD : \(\large{\sqrt{(-5-2)^2 + (-3 + 3)^2 } = \sqrt{(-7)^2 + 0^2} = \sqrt{(-7)^2} = 7 }\) AD : \(\large{\sqrt{(-5+3)^2 + (-3 -2 )^2 } = \sqrt{(4 + 25) } = \sqrt{29} }\) So , it is clear that , BC = AD and AB = CD that is opposite sides are equal of the quadrilateral ABCD. Thus, first of all, ABCD is a parallelogram . Now, area of the parallelogram = base * corresponding height Base (let us say that it is CD) and Corresponding height will be : (Say it is AM ) CD = \(7\) [Found above] The coordinates of A is : (-3,2) The coordinates of M is : (-3,-3) AM = \(\sqrt{(0)^2 + (5)^2 } = \sqrt{25} = 5\) Therefore area = CD * AM = 7 * 5 = 35 sq. unit For perimeter: AB + BC + CD + AD = \(7 + \sqrt{29} + 7 + \sqrt{29} \) = \(14 + 2\sqrt{29} \)

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