anonymous
  • anonymous
n -^4 w^0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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phi
  • phi
anything to the 0 power is 1. examples: 2^0 = 1 3^0= 1 a^0 =1
anonymous
  • anonymous
ohhh yeah so like w^0 is 1?
phi
  • phi
an negative exponent can be changed to a positive exponent using this rule: \[ x^{-a} = \frac{1}{x^a} \] and \[ x^{a} = \frac{1}{x^{-a}} \]

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More answers

phi
  • phi
"flip" the number and change the sign of the exponent.
anonymous
  • anonymous
flip what number
phi
  • phi
is the problem \[ n^{-4} w^0 \]?
anonymous
  • anonymous
yes
phi
  • phi
so you know w^0= 1 and you have \[ n^{-4} \cdot 1 = n^{-4} \]
phi
  • phi
if you don't want a -4 for the exponent , use this rule: \[ x^{-a} = \frac{1}{x^a}\]
phi
  • phi
Do you understand the rule ?
anonymous
  • anonymous
i dont understand the rule but i understand the step before that..
phi
  • phi
match your problem \[ n^{-4} \] with \[ x^{-a} \] the "n" goes with the "x" and the 4 goes with the "a" the rule is \[ x^{-a} = \frac{1}{x^a}\] the idea is rewrite your problem so it matches the rule
phi
  • phi
n^-4 = ?
anonymous
  • anonymous
is there any other way to do this because i know the answer but i just dont understand the steps
phi
  • phi
what is the answer ?
anonymous
  • anonymous
1/16
phi
  • phi
do they tell you that n is some number ?
anonymous
  • anonymous
oh yeah n=-2 and w=5
phi
  • phi
ok, that makes sense. First, do you know that the little numbers (the exponents) are a "short-hand" people came up with to save typing? n^3 means n*n*n (n times itself 3 times) n^1 means n n^2 means n*n n^4 means n*n*n*n n^10 is too much to type out... does that part make sense ?
anonymous
  • anonymous
yes
phi
  • phi
next, people decided that n^0 (or anything to the 0 power) is 1 (so your w^0 is 1 in your problem) then they said: "what about negative exponents?" like \( n^{-1} \) ? that means it is 1 divided by n^1: \( \frac{1}{n^1} \) if you see a negative exponent, rewrite the expression by dividing it into 1 \[ x^{-1} = \frac{1}{x^1} \\ x^{-2} = \frac{1}{x^2}\\ x^{-3} = \frac{1}{x^3} \] and so on do you follow ?
phi
  • phi
so, for your problem \[ n^{-4} w^0 = \frac{w^0}{n^4} \]
phi
  • phi
as you know w^0 is 1, and n^4 is n*n*n*n, so you can write this as \[ n^{-4} w^0 = \frac{w^0}{n^4} = \frac{1}{n \cdot n \cdot n\cdot n} \]
phi
  • phi
to get the number, replace every n with -2 (because n= -2) \[ \frac{1}{n \cdot n \cdot n\cdot n} = \frac{1}{-2 \cdot -2 \cdot -2\cdot -2} \]
phi
  • phi
now multiply -2*-2 * -2 *-2 to simplify
anonymous
  • anonymous
16
anonymous
  • anonymous
OOOOOH I GET THANK YOU SO MUCH!!!!
phi
  • phi
\[ \frac{1}{n \cdot n \cdot n\cdot n} = \frac{1}{-2 \cdot -2 \cdot -2\cdot -2} = \frac{1}{16} \]

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