A man invests x amount of money at 2% interest. The next day he invests $800 more than the previous morning into an account that earns 4% interest. At the end of one year he has earned a total of $112 in interest. How much money was invested in each account?
Which of the following equations could be used to solve the problem?
0.02x + 0.04(800) = 112
0.02x + 0.04(x + 800) = 112
0.04x + 0.02(x + 800) = 112
0.04x - 0.04(x + 800) = 112
Stacey Warren - Expert brainly.com
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Let's rewrite our 2% as a decimal, \(\large 0.02\).
Our amount invested is represented by \(\large x\).
The interest based off of the initial investment can be calculated by multiplying our `amount` by our `interest rate`.
Understand how we came up with that part of the problem?
The next day, our amount has increased by $800.
It's the same amount \(\large x\), but increased by 800.
We can write it like this \(\large (x+800)\).
And this amount is invested at 4%, or as a decimalm \(\large 0.04\)
Do you think you can figure out how the second part should look, based on what we did for the first day?
That's so confusing you could put it in latin and i would understand it better. Just tell me what the anwser is? lol