anonymous
  • anonymous
Slope of a tangent line of graph at P
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
So far i had ((3/x)-(3/4)) divided by (x-4). I simplified that out to -3/4x for the slope but that was incorrect. Am i approaching it wrong?
hartnn
  • hartnn
how did you simplify the numerator, ((3/x)-(3/4) ?

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anonymous
  • anonymous
I made it 12-3x all over 4x.
hartnn
  • hartnn
yes, 12-3x = 3 (4-x) right ? = -3 (x-4) and did you cancel out x-4 then ?
anonymous
  • anonymous
Yup, i was left with -3/4x.
anonymous
  • anonymous
The extra x is messing it up i guess?
hartnn
  • hartnn
i see, you did so, you have limit x=>-4 -3/4x not just -3/4x you need to substitute x= -4 in limit x=>-4 (-3/4x)
anonymous
  • anonymous
Woh wait where are you getting -4? Why do i plug that in for x??
hartnn
  • hartnn
like lim x->a f(x) = f(a) we substitute x=a here it'll be -3/4(-4)
hartnn
  • hartnn
the limit is x->a we are taking the limit AT POINT P and x-co-ordinate at P is 4 ohh...its 4 , not -4 :P sorry
hartnn
  • hartnn
lim x->4 -3/4x = -3/4(4)
anonymous
  • anonymous
So its -3/16? I thought the x-4's both canceled out, so why do we use that for x?
anonymous
  • anonymous
Oh *facepalms* i see now.
anonymous
  • anonymous
Forgot about P(4,3/4)
hartnn
  • hartnn
yes, -3/16 as i said, we need derivative at point P, whose x-coordinate is 4....
anonymous
  • anonymous
Alright, so then the equation for the tangent line at P would be y-4=-3/16 (x-3/4)
anonymous
  • anonymous
Still need to simplify of couse.
hartnn
  • hartnn
y-y1 = m (x-x1) i think you interchanged x and y
hartnn
  • hartnn
y-3/4 = -3/16 (x-4) isn't it?
anonymous
  • anonymous
Oh my bad. So it should end up as y=-3/16x +3/2
hartnn
  • hartnn
yes. :)
anonymous
  • anonymous
Thanks again : )
hartnn
  • hartnn
welcome ^_^

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