Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers. @mathstudent55
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Let the smallest odd integer equal x.
How would you express the next larger one in terms of x?
Look at the odd integer 5.
The next larger odd integer is 7.
If you start with 5, what operation would you do to get to 7?
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7 is 2 more than 5. Any odd integer is 2 more than the previous one.
so whts the answer
If you let the smallest integer be represented by x, the next larger one is 2 more than x, or x + 2. Then the 3rd integer is 2 more than x + 2, or x + 2 + 2 which is x + 4. The largest of the integers is x + 6.
The 4 integers are x, x + 2, x + 4, x + 6
The problem states that the product of the two smaller ones, x(x + 2), is 64 less than the product of the two larger ones, (x + 4)(x + 6).
Now we can write an equation.
The equation is
x(x + 2) = (x + 4)(x + 6) - 64
Now you need to solve the equation to get x. That will give you smallest integer. Then add 2, 4, and 6, to x to get the other odd integers.