anonymous
  • anonymous
Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers. @mathstudent55
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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mathstudent55
  • mathstudent55
Let the smallest odd integer equal x. How would you express the next larger one in terms of x?
anonymous
  • anonymous
idk
mathstudent55
  • mathstudent55
Look at the odd integer 5. The next larger odd integer is 7. If you start with 5, what operation would you do to get to 7?

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mathstudent55
  • mathstudent55
7 is 2 more than 5. Any odd integer is 2 more than the previous one.
anonymous
  • anonymous
so whts the answer
mathstudent55
  • mathstudent55
If you let the smallest integer be represented by x, the next larger one is 2 more than x, or x + 2. Then the 3rd integer is 2 more than x + 2, or x + 2 + 2 which is x + 4. The largest of the integers is x + 6. The 4 integers are x, x + 2, x + 4, x + 6 The problem states that the product of the two smaller ones, x(x + 2), is 64 less than the product of the two larger ones, (x + 4)(x + 6). Now we can write an equation.
mathstudent55
  • mathstudent55
The equation is x(x + 2) = (x + 4)(x + 6) - 64 Now you need to solve the equation to get x. That will give you smallest integer. Then add 2, 4, and 6, to x to get the other odd integers.
mathstudent55
  • mathstudent55
@shortie212 Here it is

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