anonymous
  • anonymous
Ignore air resistance. A diver starts 30 feet above the water (about the height of an Olympic platform diver). What is the diver’s velocity at impact?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@experimentX can u help?
experimentX
  • experimentX
\[ v^2 = u^2 + 2 a s\] u = 0 (initial vecolity v = final velocity a = acceleration due to gravity (9.8 m/s^2) <-- change it into feet/sec^2 s = 30 feet calculate it
anonymous
  • anonymous
here is what i ddi so far can u check? 2(9.8) (9.14) = vf^2 - 0^2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
using second equation of motion 2as = vf^2 -vi^2
experimentX
  • experimentX
seems okay https://www.google.com/search?q=convert+30+feet+into+meters&rlz=1C1ASUT_enNP447NP447&oq=change+30+feet+into+&aqs=chrome.1.57j0l3j62l2.9186j0&sourceid=chrome&ie=UTF-8
anonymous
  • anonymous
putting it as a = g =9.8 s = 30 feet = i changed it in meters vi =0 then to find vf
anonymous
  • anonymous
ok
experimentX
  • experimentX
ok ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.