anonymous
  • anonymous
What is the vertex of the function f(x)=2x^2+4x-16?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
(-2,4) ?
Jhannybean
  • Jhannybean
standard form y = a(x-h)^2+k y= 2x^2 + 4x - 16 move the 16 to the other side y + 16 = 2x^2 + 4x factor out a 2 from the right side. y + 16 = 2(x^2 + 2x) complete the square y + 16 + 2( 1 ) = 2( x^2 +2x + 1) simplify. y + 18 = 2(x + 1)^2 y = 2(x + 1)^2 - 18 put it back in standard form. y = 2( x - (-1))^2 + (-18)
anonymous
  • anonymous
Refer to the attached Mathematica calculation.
1 Attachment

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Jhannybean
  • Jhannybean
Am i wrong? :\
Jhannybean
  • Jhannybean
Oh i see.
Jhannybean
  • Jhannybean
WELL!! we got the same thing, lol. (-1,-18) for the vertex. Thanks @robtobey :)

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