anonymous
  • anonymous
Trig ratios please help!
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
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anonymous
  • anonymous
@whpalmer4 @RadEn @rulnick @timo86m @Hero @jim_thompson5910 @KingGeorge @Zarkon @cwrw238
Hero
  • Hero
There's a couple ways to do this. You have to either find the angle or find the other side.

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More answers

Hero
  • Hero
You know that \(\cos\theta = \frac{\text{adj}}{\text{hyp}} = \frac{2}{5}\) So: |dw:1370471031374:dw|
anonymous
  • anonymous
Ok. so two more ratios could be sin(theta)=x/5 and tan(theta)=x/2?
anonymous
  • anonymous
If so, how do I get 3 more?
Hero
  • Hero
Well, you have to find x
Hero
  • Hero
And the other trig ratios are sec, csc, and cot
Hero
  • Hero
tan and sin
anonymous
  • anonymous
how do I find x? Don't I need the angle measure?
Hero
  • Hero
Pythagorean Theorem
anonymous
  • anonymous
OH wait I know how, we have 2 sides
anonymous
  • anonymous
how do sec, csc, and cot work?
anonymous
  • anonymous
I don't know the ratios for those
Jhannybean
  • Jhannybean
sec = 1/ cos(x) csc = 1/ sin(x) cot (x) = cos (x)/ sin (x)
anonymous
  • anonymous
Haha, thanks guys.
Hero
  • Hero
By the way, it's fractal flake, not snow flake
anonymous
  • anonymous
is this right? sec=1/cos(4.583)
anonymous
  • anonymous
or does the x stand for theta?
Hero
  • Hero
Actually....let me get the right ratios for you
anonymous
  • anonymous
Or wait, idk, I'm a little confused, can you help me with the last 3? I got 4.583 for the last side, what now?
Hero
  • Hero
You need the right trig ratios for this
Jhannybean
  • Jhannybean
if cos = adj / hyp then sec would be the reciprocal hyp/adj if csc = 1/ sin (x) and sin (x) = opp / hyp then csc = hyp/ opp if cot = cos / sin .....?
Hero
  • Hero
\[\sec\theta = \frac{hyp}{adj}\]\[\csc\theta = \frac{hyp}{opp}\]\[\cot\theta = \frac{adj}{opp}\]
Jhannybean
  • Jhannybean
oh my goodness. tan = y / x
Jhannybean
  • Jhannybean
and cot = x / y derp....
Hero
  • Hero
In other words, these ratios will include whole numbers as part of the fractions such as 2/5, not any decimals or anything
anonymous
  • anonymous
But my third side is a decimal, I can't have a decimal in my fraction?
Hero
  • Hero
@Jhannybean, please do not use phrases such as derp...it is interpeted as name calling which is inappropriate
Jhannybean
  • Jhannybean
Wow really, i was referring to myself, but ok.
Hero
  • Hero
@kirk.freedman, use the pythagorean theorem to find the third side x.
anonymous
  • anonymous
I got 4.583 for the third side
Hero
  • Hero
@Jhannybean, I don't want to turn this into an argument...you didn't specify that you were referring to yourself.
anonymous
  • anonymous
so sin(theta)=4.583/5? Can I leave the decimal there?
Hero
  • Hero
Did you find the third side using pythagorean theorem? You cannot do this any other way @kirk.freedman
Jhannybean
  • Jhannybean
and you don't need a decimal, just leave it under a square root. what is \[\large \sqrt{5^{2}-2^{2}}\] ? And @Hero Alrighty.
Hero
  • Hero
2^2 + x^2 = 5^2 solve for x @kirk.freedman
anonymous
  • anonymous
4.582, as I said
anonymous
  • anonymous
or sqrt(21)
Hero
  • Hero
sqrt(21)
Jhannybean
  • Jhannybean
there you go.
anonymous
  • anonymous
Wait so I just leave it as sqrt(21) in my ratios?
Hero
  • Hero
Yes
Jhannybean
  • Jhannybean
Decimals just make it harder to evaluate. You'd rather keep your values looking pretty.
anonymous
  • anonymous
Thanks! Who should I medal? haha both were helpful
anonymous
  • anonymous
I'll give it to the one with less :P
Jhannybean
  • Jhannybean
And now that you've found all sides of your triangle... you can just use the formulas @Hero gave you, to evaluate for whatever you're looking for.
Jhannybean
  • Jhannybean
I think Hero deserves it since he helped you with the problem.
Hero
  • Hero
"Give it to the one with less"...that should not be the criteria for giving a medal. You give a medal to the person with the "Best Response"
Hero
  • Hero
^What @Jhannybean said
anonymous
  • anonymous
Well both were equally as helpful, sorry.
Jhannybean
  • Jhannybean
Thank you guys.
anonymous
  • anonymous
It's just a medal, forget it
anonymous
  • anonymous
thanks to both
Hero
  • Hero
Medals add up. That's why I have almost 5000 of them
Jhannybean
  • Jhannybean
-_- I'll get there some day.
Hero
  • Hero
At some point, receiving a medal is worth more than just a medal.
Jhannybean
  • Jhannybean
Started OpenStudy about 4 weeks ago.
Hero
  • Hero
Welcome to OS

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