anonymous
  • anonymous
i keep trying to do this question but i can't get it right...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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abb0t
  • abb0t
Can you show us the question and your work to see where you are stuck at? That way we can guide you from where you're stuck :)
anonymous
  • anonymous
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anonymous
  • anonymous
and the question is?

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abb0t
  • abb0t
Lol. I'm leaving. I can't handle this.
anonymous
  • anonymous
i just posted the pic
whpalmer4
  • whpalmer4
Yeah, but the picture doesn't tell us what to do, nor where you are getting stuck. Looking at the triangle and the answer choices, I take it the problem is to find the perimeter?
anonymous
  • anonymous
And a very nice picture it is. Where should we hang it?
anonymous
  • anonymous
im sorry lol...im supposed to find the perimeter
whpalmer4
  • whpalmer4
And what results have you gotten when you've tried? It's possible you've gotten the right answer and just didn't recognize it!
anonymous
  • anonymous
i got 105. CD is 25,DE is 40 and EC is 40.
whpalmer4
  • whpalmer4
Oh, I guess I was a bit too optimistic :-) How are you finding CD? I think I know what you did wrong...
whpalmer4
  • whpalmer4
You miscounted when you did CE, btw — the side of the triangle is 3, not 2, unlike when you do DE. The other problem is that you forgot to take the square roots...so you are adding c^2 instead of c
anonymous
  • anonymous
i used the distance formula
anonymous
  • anonymous
when do i do square roots?
whpalmer4
  • whpalmer4
Okay, you didn't read the coordinates of all of your points quite correctly, then. Distance formula: \[d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
whpalmer4
  • whpalmer4
So to find the length of CD from (-3,1) to (1,4) \[CD = \sqrt{(-3-1)^2+(1-4)^2} = \sqrt{(-4)^2+(-3)^2} = \sqrt{16+9} = \sqrt{25} = 5\]
whpalmer4
  • whpalmer4
Now do the other two and tell me what you get.
whpalmer4
  • whpalmer4
Note that DE and CE are NOT the same length...
anonymous
  • anonymous
5+6.3+6.7=18
anonymous
  • anonymous
thank you!!
whpalmer4
  • whpalmer4
Very good!

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