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Better for us to use illustrations to prove our point.
@experimentX check this out:
|dw:1370500622725:dw| Two loops of wire.
As you can see BOTH are closed. So current can flow in both and lenz's law is still in effect.
|dw:1370500680648:dw| The X mark spot, is now open meaning the loop is not a "closed" path.
current can NOT flow through both of them regardless of the size.
Yea, but again. Having a larger thickness means there will be more charge to flow from a higher potential to a lower one. But think about it, even if EMF was applied to move te charge from a high potential to low, it can't mainly because the path in which it can move in is open. So it is stuck in the same place unable to move.
but generally when we consider a wire, we mean think wire ... of course there is no eddy current. so faraday's law comes in to play.
So if there was a larger coil in a open circuit will there be induced current? Can it oppose a magnet that is the cause of "change"? I assume that there is no flow of current in a coil that is a series of loops thus as you said the cannot spin and finally, the magnet moves freely with not magnetic resistance?
no it won't ..
What wont? The magnet or the current flow?
the current won't flow and the magnet won't be opposed
you sure 100% :P? I have a good essay to talk about, and it revoles about using methods that lenz's law is not effective! I want to be sure as much as I can!
Well ... you meant|dw:1370502000264:dw|
|dw:1370502300630:dw| Im using something like this diagram. I'll even do an experiment for this, and pass a strong magnet in and out of the coil while the circuit is open.
Fascinating thing, but its a really interesting idea you told me about the large bar... But, what if the coil had thick wires? It certainly will oppose the magnet!
thick means ... too thick for a wire. watch this video lecture http://www.youtube.com/watch?v=qxuGDEz8wDg
be back when im done.
Back, very interesting lecture! Still current flows in a "open" loop. The resistance is MUCH higher so the magnetic resistance is just less. The coil in my diagram will generate a current and it will oppose the magnet but very very very very weak resistance. Perhaps unnoticeable, but still exists.
the current that you are talking about is from the diffusion of charge .. it is negligible
@experimentX I don't have to worry about a magnet passing through a coil in a open circuit, its going to have 0 magnet resistance, its velocity will not drop at all. I got the idea, thanks.