anonymous
  • anonymous
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Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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Jhannybean
  • Jhannybean
\[\large \sqrt[3]{x^2}*\sqrt[4]{x}= x^{2/3}*x^{1/4} = x^{(2/3)+(1/4)}\]
Jhannybean
  • Jhannybean
first simplify \[\large \frac{2}{3}+\frac{1}{4}\]
Jhannybean
  • Jhannybean
good job :) this is now the exponent of your base x.

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Jhannybean
  • Jhannybean
|dw:1370501661566:dw| so your outer power is the power of your radical (or square root) and the inner power is the one that multiplies to your base "x"
Jhannybean
  • Jhannybean
lol no problem. do you understand how it works? I think of it like.. "11/12" the "12" is faster and can "jump" and land on the front of the square root while the "11" is the fat one that stays next to its owner. Haha.

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