## Emily778 2 years ago What is the value of x, given that PQ is parallel to BC?

1. Emily778

2. Emily778

@Nurali

3. mayankdevnani

@Emily778 do you know what is Thales Theorem???

4. Emily778

NO

5. Emily778

@jim_thompson5910

6. mayankdevnani

thales theorem states that $\huge \frac{AP}{PB}=\frac{AQ}{QC}$

7. mayankdevnani

where AP=8,PB=32,AQ=x and QC=36.

8. jim_thompson5910

the two triangles are similar, so you can say 8/(32+8) = x/(36+x) solve for x

9. mayankdevnani

can you solve it @Emily778

10. Emily778

8 x 32?

11. mayankdevnani

$\huge \frac{8}{32}=\frac{x}{36}$ Can you solve for x???

12. Emily778

.25

13. Emily778

or..Do I cross multiply?

14. mayankdevnani

yeah!!

15. jim_thompson5910

8/(32+8) = x/(36+x) 8/40 = x/(36+x) 8(36+x) = 40x ... ... ... x = ??

16. Emily778

288

17. mayankdevnani

what x=288????

18. Emily778

x=18?

19. mayankdevnani

no, wrong

20. Emily778

9?

21. mayankdevnani

correct

22. ganeshie8

left side you see, 8 is 4 times lees than 32 so right side, 9 has to 4 times less than 36. 9 works.