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Emily778
 one year ago
What is the value of x, given that PQ is parallel to BC?
Emily778
 one year ago
What is the value of x, given that PQ is parallel to BC?

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mayankdevnani
 one year ago
Best ResponseYou've already chosen the best response.0@Emily778 do you know what is Thales Theorem???

mayankdevnani
 one year ago
Best ResponseYou've already chosen the best response.0thales theorem states that \[\huge \frac{AP}{PB}=\frac{AQ}{QC}\]

mayankdevnani
 one year ago
Best ResponseYou've already chosen the best response.0where AP=8,PB=32,AQ=x and QC=36.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0the two triangles are similar, so you can say 8/(32+8) = x/(36+x) solve for x

mayankdevnani
 one year ago
Best ResponseYou've already chosen the best response.0can you solve it @Emily778

mayankdevnani
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge \frac{8}{32}=\frac{x}{36}\] Can you solve for x???

Emily778
 one year ago
Best ResponseYou've already chosen the best response.0or..Do I cross multiply?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.08/(32+8) = x/(36+x) 8/40 = x/(36+x) 8(36+x) = 40x ... ... ... x = ??

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0left side you see, 8 is 4 times lees than 32 so right side, 9 has to 4 times less than 36. 9 works.
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