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anonymous
 3 years ago
What is the value of x, given that PQ is parallel to BC?
anonymous
 3 years ago
What is the value of x, given that PQ is parallel to BC?

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mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.1@Emily778 do you know what is Thales Theorem???

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.1thales theorem states that \[\huge \frac{AP}{PB}=\frac{AQ}{QC}\]

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.1where AP=8,PB=32,AQ=x and QC=36.

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0the two triangles are similar, so you can say 8/(32+8) = x/(36+x) solve for x

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.1can you solve it @Emily778

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge \frac{8}{32}=\frac{x}{36}\] Can you solve for x???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or..Do I cross multiply?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.08/(32+8) = x/(36+x) 8/40 = x/(36+x) 8(36+x) = 40x ... ... ... x = ??

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0left side you see, 8 is 4 times lees than 32 so right side, 9 has to 4 times less than 36. 9 works.
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