anonymous
  • anonymous
What is the value of x, given that PQ is parallel to BC?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
@Nurali
mayankdevnani
  • mayankdevnani
@Emily778 do you know what is Thales Theorem???

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anonymous
  • anonymous
NO
anonymous
  • anonymous
@jim_thompson5910
mayankdevnani
  • mayankdevnani
thales theorem states that \[\huge \frac{AP}{PB}=\frac{AQ}{QC}\]
mayankdevnani
  • mayankdevnani
where AP=8,PB=32,AQ=x and QC=36.
jim_thompson5910
  • jim_thompson5910
the two triangles are similar, so you can say 8/(32+8) = x/(36+x) solve for x
mayankdevnani
  • mayankdevnani
can you solve it @Emily778
anonymous
  • anonymous
8 x 32?
mayankdevnani
  • mayankdevnani
\[\huge \frac{8}{32}=\frac{x}{36}\] Can you solve for x???
anonymous
  • anonymous
.25
anonymous
  • anonymous
or..Do I cross multiply?
mayankdevnani
  • mayankdevnani
yeah!!
jim_thompson5910
  • jim_thompson5910
8/(32+8) = x/(36+x) 8/40 = x/(36+x) 8(36+x) = 40x ... ... ... x = ??
anonymous
  • anonymous
288
mayankdevnani
  • mayankdevnani
what x=288????
anonymous
  • anonymous
x=18?
mayankdevnani
  • mayankdevnani
no, wrong
anonymous
  • anonymous
9?
mayankdevnani
  • mayankdevnani
correct
ganeshie8
  • ganeshie8
left side you see, 8 is 4 times lees than 32 so right side, 9 has to 4 times less than 36. 9 works.

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