Emily778
What is the value of x, given that PQ is parallel to BC?



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Emily778
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Emily778
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@Nurali

mayankdevnani
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@Emily778 do you know what is Thales Theorem???

Emily778
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NO

Emily778
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@jim_thompson5910

mayankdevnani
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thales theorem states that \[\huge \frac{AP}{PB}=\frac{AQ}{QC}\]

mayankdevnani
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where AP=8,PB=32,AQ=x and QC=36.

jim_thompson5910
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the two triangles are similar, so you can say
8/(32+8) = x/(36+x)
solve for x

mayankdevnani
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can you solve it @Emily778

Emily778
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8 x 32?

mayankdevnani
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\[\huge \frac{8}{32}=\frac{x}{36}\]
Can you solve for x???

Emily778
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.25

Emily778
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or..Do I cross multiply?

mayankdevnani
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yeah!!

jim_thompson5910
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8/(32+8) = x/(36+x)
8/40 = x/(36+x)
8(36+x) = 40x
...
...
...
x = ??

Emily778
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288

mayankdevnani
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what x=288????

Emily778
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x=18?

mayankdevnani
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no, wrong

Emily778
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9?

mayankdevnani
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correct

ganeshie8
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left side you see, 8 is 4 times lees than 32
so right side, 9 has to 4 times less than 36.
9 works.