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Emily778 Group Title

What is the value of x, given that PQ is parallel to BC?

  • one year ago
  • one year ago

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  1. Emily778 Group Title
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    • one year ago
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  2. Emily778 Group Title
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    @Nurali

    • one year ago
  3. mayankdevnani Group Title
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    @Emily778 do you know what is Thales Theorem???

    • one year ago
  4. Emily778 Group Title
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    NO

    • one year ago
  5. Emily778 Group Title
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    @jim_thompson5910

    • one year ago
  6. mayankdevnani Group Title
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    thales theorem states that \[\huge \frac{AP}{PB}=\frac{AQ}{QC}\]

    • one year ago
  7. mayankdevnani Group Title
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    where AP=8,PB=32,AQ=x and QC=36.

    • one year ago
  8. jim_thompson5910 Group Title
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    the two triangles are similar, so you can say 8/(32+8) = x/(36+x) solve for x

    • one year ago
  9. mayankdevnani Group Title
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    can you solve it @Emily778

    • one year ago
  10. Emily778 Group Title
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    8 x 32?

    • one year ago
  11. mayankdevnani Group Title
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    \[\huge \frac{8}{32}=\frac{x}{36}\] Can you solve for x???

    • one year ago
  12. Emily778 Group Title
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    .25

    • one year ago
  13. Emily778 Group Title
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    or..Do I cross multiply?

    • one year ago
  14. mayankdevnani Group Title
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    yeah!!

    • one year ago
  15. jim_thompson5910 Group Title
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    8/(32+8) = x/(36+x) 8/40 = x/(36+x) 8(36+x) = 40x ... ... ... x = ??

    • one year ago
  16. Emily778 Group Title
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    288

    • one year ago
  17. mayankdevnani Group Title
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    what x=288????

    • one year ago
  18. Emily778 Group Title
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    x=18?

    • one year ago
  19. mayankdevnani Group Title
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    no, wrong

    • one year ago
  20. Emily778 Group Title
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    9?

    • one year ago
  21. mayankdevnani Group Title
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    correct

    • one year ago
  22. ganeshie8 Group Title
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    left side you see, 8 is 4 times lees than 32 so right side, 9 has to 4 times less than 36. 9 works.

    • one year ago
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