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Emily778

  • 2 years ago

What is the value of x, given that PQ is parallel to BC?

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  1. Emily778
    • 2 years ago
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  2. Emily778
    • 2 years ago
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    @Nurali

  3. mayankdevnani
    • 2 years ago
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    @Emily778 do you know what is Thales Theorem???

  4. Emily778
    • 2 years ago
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    NO

  5. Emily778
    • 2 years ago
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    @jim_thompson5910

  6. mayankdevnani
    • 2 years ago
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    thales theorem states that \[\huge \frac{AP}{PB}=\frac{AQ}{QC}\]

  7. mayankdevnani
    • 2 years ago
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    where AP=8,PB=32,AQ=x and QC=36.

  8. jim_thompson5910
    • 2 years ago
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    the two triangles are similar, so you can say 8/(32+8) = x/(36+x) solve for x

  9. mayankdevnani
    • 2 years ago
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    can you solve it @Emily778

  10. Emily778
    • 2 years ago
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    8 x 32?

  11. mayankdevnani
    • 2 years ago
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    \[\huge \frac{8}{32}=\frac{x}{36}\] Can you solve for x???

  12. Emily778
    • 2 years ago
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    .25

  13. Emily778
    • 2 years ago
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    or..Do I cross multiply?

  14. mayankdevnani
    • 2 years ago
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    yeah!!

  15. jim_thompson5910
    • 2 years ago
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    8/(32+8) = x/(36+x) 8/40 = x/(36+x) 8(36+x) = 40x ... ... ... x = ??

  16. Emily778
    • 2 years ago
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    288

  17. mayankdevnani
    • 2 years ago
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    what x=288????

  18. Emily778
    • 2 years ago
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    x=18?

  19. mayankdevnani
    • 2 years ago
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    no, wrong

  20. Emily778
    • 2 years ago
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    9?

  21. mayankdevnani
    • 2 years ago
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    correct

  22. ganeshie8
    • 2 years ago
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    left side you see, 8 is 4 times lees than 32 so right side, 9 has to 4 times less than 36. 9 works.

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