anonymous
  • anonymous
plae answer this
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
simplify it and make it look simpler Write it alllll out ax*ax+bx=c... etc
anonymous
  • anonymous
Once thats done tell me whatcha got
anonymous
  • anonymous
oh okgive me a sec ok :)

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anonymous
  • anonymous
@Ashleyisakitty hey check this out
anonymous
  • anonymous
what math are you in?
anonymous
  • anonymous
are you in algebra 2?
anonymous
  • anonymous
or dont accept my help...? thats fine also
anonymous
  • anonymous
ru in CA
ganeshie8
  • ganeshie8
hint : y = a(x-h)^2 will have equal roots
ganeshie8
  • ganeshie8
that makes : b^2-4ac = 0
anonymous
  • anonymous
I have ansurs
ganeshie8
  • ganeshie8
still stuck wid this @msingh ?
ganeshie8
  • ganeshie8
i assume the hint i gave you didnt make sense to you
Loser66
  • Loser66
@msingh I want to confirm the original one, the right handside is a(x-p)^2 is it p or b?
anonymous
  • anonymous
its a(x-p)^2
Loser66
  • Loser66
ok |dw:1370537094324:dw|
Loser66
  • Loser66
|dw:1370537247731:dw|
Loser66
  • Loser66
|dw:1370537293365:dw|
Loser66
  • Loser66
got it? can follow?
Loser66
  • Loser66
now you have b = -2ap ---> p = b/-2a ---> p^2 = b^2 / 4a^2 and c = ap^2 ---> p^2 = c/a
Loser66
  • Loser66
from then, you have \[\frac{b^2}{4a^2} = \frac{c}{a}\]
Loser66
  • Loser66
or \[\frac{b^2}{4a}=c\]
Loser66
  • Loser66
or \[b^2 = 4ac\]
Loser66
  • Loser66
is it clear now? know how to get it?
anonymous
  • anonymous
okay , now i got it

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