anonymous
  • anonymous
A concrete cube of side 0.60 m and uniform density 2.0 × 103 kg m–3 is lifted 5.0 m vertically by a crane. What is the change in potential energy of the cube?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
mos1635
  • mos1635
formula for potential energy??
anonymous
  • anonymous
i just need an answer if however i require the formula
mos1635
  • mos1635
????

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
these are the answers: A 2.2 kJ B 21 kJ C 59 kJ D 450 kJ
anonymous
  • anonymous
its B but i wanna know how to get the answer
mos1635
  • mos1635
what is the formula for potential energy??
anonymous
  • anonymous
i know that its equal to mgh m for mass, g equals to 9.81 and h for height but i still can solve it; density is related as: mass over volume and well im not sure how to solve it
mos1635
  • mos1635
|dw:1370515786355:dw|
anonymous
  • anonymous
0.6 X3 as the sides of the cube?
mos1635
  • mos1635
0.6^3=0.6*0.6*0.6=0.216
anonymous
  • anonymous
ok and next?
mos1635
  • mos1635
find mass
anonymous
  • anonymous
we have the density so i guess we need the volume and we find the mass
mos1635
  • mos1635
\[d=\frac{ m }{ V }\]
mos1635
  • mos1635
but you have allready find volume
anonymous
  • anonymous
oh yes its 0.216
mos1635
  • mos1635
\[V _{cube}=side ^{3}=a ^{3}=0.6^{3}=0.216\]
anonymous
  • anonymous
ok thanks just found it thanks for your help :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.