anonymous
  • anonymous
Algebra equation...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1370530656412:dw|
phi
  • phi
try factoring the denominators
phi
  • phi
as the first step in finding a common denominator: 2(x+3)(x-3)

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phi
  • phi
can you finish ?
anonymous
  • anonymous
I think... Should I factor 2x+6 too and then multiply that with 2(x+3)(x-3) to get my common denominator?
phi
  • phi
you want to keep the common denominator as simple as possible 2x+6 is 2(x+3) if you multiply it by (x-3) you get 2(x+3)(x-3) i.e. the common denominator of course, you also have to multiply the top by (x-3)
phi
  • phi
if you factor you get \[ \frac{(x+1)}{2(x+3) } + \frac{-9}{(x+3)(x-3)} = \frac{(x-2)}{2(x-3)} \]
phi
  • phi
now multiply the first fraction by (x-3)/(x-3) the 2nd fraction by 2/2 and the last by (x+3)/(x+3)
phi
  • phi
once everything has the same denominator, you can equate the tops, and solve for x
anonymous
  • anonymous
I got x=-18. Is that right?
phi
  • phi
you could put x=-18 into the original equation. Does it work ?
phi
  • phi
\[\frac{(x+1)(x-3)}{2(x+3)(x-3) } + \frac{-9\cdot 2}{2(x+3)(x-3)} = \frac{(x-2)(x+3)}{2(x-3)(x+3)} \] now solve just the top: \[ (x+1)(x-3) -18= (x-2)(x+3) \]
anonymous
  • anonymous
So -18 doesn't work because those don't equal each other.
phi
  • phi
now multiply out and simplify: \[ (x+1)(x-3) -18= (x-2)(x+3) \]
anonymous
  • anonymous
I keep getting that 339=330
phi
  • phi
what do you get for (x+1)(x-3) ?
anonymous
  • anonymous
I just resolved it and got -5 which actually works! Thanks for the help! :)

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