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let O be the center of circle.
first, find \(\angle OBA\)
How would i find that -__ - ?
There's no O ?
Oh i get what you mean, O represents the center of the circle.
Yes. draw it you will see how to find \(\angle OBA\)
Ignore the double o
It was only suppose to be one -__ -
63, because a circle is 360 degrees and i still need the degrees from the tangent-chord
let me show u
that angle at the center would be 126
That equals 360 so what would be left for the outside segment ?
Also i don't know how you got 126
126 = 360-234
minor arc = 360-major arc
I got that but i thought i needed to divide it since the tangent-chord was left -__ -
lets go step by step
radius and tangent make 90 degree angles. so that angle is 90
So everything time i look for a tangent-chord i add up what i find as the radius by 90 then
Yes its 90 + that angle
how did u get that... no angle can be greater than 360
Didn't you mean that i add up the 126 + 234 and then add 90 or did you just mean 126 + 90?
nope look at the pic
stare at it for some time.
Just to be clear you did this 180 - 126 = 54/2 = 27 ?
great ! we take half of 54 cuz, the triangle over there is isosceles. the base angles are equal, so each equal to half of 54