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Emily778Best ResponseYou've already chosen the best response.0
@FutureMathProfessor Please help! Given reward if so!
 10 months ago

FutureMathProfessorBest ResponseYou've already chosen the best response.0
dw:1370548165122:dw
 10 months ago

FutureMathProfessorBest ResponseYou've already chosen the best response.0
dw:1370548310040:dw
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
oh my goodness. lol.
 10 months ago

mitodoteiraBest ResponseYou've already chosen the best response.2
\[a ^{2}+b ^{2}=c ^{2}\] \[8 ^{2}+15 ^{2}=x ^{2}\] \[64+225=x ^{2}\] \[x ^{2}=289\] \[x=\sqrt{289}\] \[x=17\]
 10 months ago

Emily778Best ResponseYou've already chosen the best response.0
@mitodoteira Can you please help with one more?
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
Aww that's not being a good sport.
 10 months ago

arafatxBest ResponseYou've already chosen the best response.0
The question didn't ask for x, should be 17^2 or 289
 10 months ago

mitodoteiraBest ResponseYou've already chosen the best response.2
Emily, what is the other question?
 10 months ago

Emily778Best ResponseYou've already chosen the best response.0
In triangle ABC, <A is a right angle and m<B= 45 degrees. Find BC. If your answer is not and integer, leave in simplest form. @mitodoteira
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
the length of the missing side would be what @arafatx mentioned. You can always plug it back in to the pythagorean identity to check your answer. a^2 +b^2 = c^2 (15)^2 + (8)^2 = (sqrt (289))^2 225 + 64 = 289
 10 months ago

Emily778Best ResponseYou've already chosen the best response.0
is that for the second one?
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
and for that question,you have a 454590 triangle, therefore your proportions are 1:1:1*sqrt(2) By that i mean both of your base legs are the same and to find the hypotenuse you're going to multiply your base leg * sqrt(2)
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
b1 = 12, b2 = 12, hypotenuse = b1*sqrt(2)
 10 months ago

mitodoteiraBest ResponseYou've already chosen the best response.2
Since <B is 45º and and <A is 90º, <C is (180(90+45)=45) 45º. Thus, the triangle is isosceles. \[a ^{2}+b ^{2}=c ^{2}\] \[12 ^{2}+12 ^{2}=x ^{2}\] \[2•144=x ^{2}\] \[x ^{2}=288\] \[x=\sqrt{288}\] \[x=12\sqrt{2}\] \[x \approx 16.97056 \approx 17\]
 10 months ago

Emily778Best ResponseYou've already chosen the best response.0
you guys are giving me 2 different answers. Which is it?
 10 months ago

mitodoteiraBest ResponseYou've already chosen the best response.2
12*sqrt(2) is about equal to 17
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
@mitodoteira c^2 = a^2 + b^2 take x = 17, c=x (17)^2 = (12)^2 + (12)^2 289 = 288 nope.
 10 months ago

mitodoteiraBest ResponseYou've already chosen the best response.2
That's because I'm rounding. The actual answer is irrational. If you look at my answer, I gave the answer to a few decimal places as well.
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
whereas we take c = 12sqrt(2) c^2= a^2 + b^2 (12sqrt(2))^2 = (12)^2 + (12)^2 288 = 288 You DO NOT round when finding lengths.
 10 months ago

mitodoteiraBest ResponseYou've already chosen the best response.2
I gave the true answer, as well as the rounded one in case she needed it for something (I was often asked to give the answer to n decimal places instead of the exact answer).
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
the "true" answer is 12* sqrt(2) according to the 454590 degree triangle.
 10 months ago

mitodoteiraBest ResponseYou've already chosen the best response.2
Yes, it is. I don't see what the problem is.
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
Emily778 You've already chosen the best response. 0 In triangle ABC, <A is a right angle and m<B= 45 degrees. Find BC. If your answer is not and integer, leave in simplest form.
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
"if the answer is not an integer, leave it in simplest form" and therefore the simplest form is 12*sqrt(2)
 10 months ago

mitodoteiraBest ResponseYou've already chosen the best response.2
What I said was 'x=12*sqrt(2), x APPROXIMATELY EQUALS 16.97056 approx 17' I am new to this community. Most others I have been to welcome extra information.
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.2
the approximation then would be longer than 16.97056. you'd have to include the whole number approximation, not rounding up to 17.
 10 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
If it's suppose to be in exact or simplified form then leave it as radicals, fractions etc. If it asks for estimation, nearest number, or approximation then that's when you round up and change the radical to a number
 10 months ago

Luigi0210Best ResponseYou've already chosen the best response.1
so your final answer for the second problem should be left as a radical.
 10 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
yeah, simplest form = \(12\sqrt{2}\)
 10 months ago
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