Find the length of the missing side.

- anonymous

Find the length of the missing side.

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- schrodinger

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- anonymous

##### 1 Attachment

- anonymous

@FutureMathProfessor Please help! Given reward if so!

- anonymous

|dw:1370548165122:dw|

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## More answers

- anonymous

|dw:1370548310040:dw|

- Jhannybean

oh my goodness. lol.

- anonymous

\[a ^{2}+b ^{2}=c ^{2}\]
\[8 ^{2}+15 ^{2}=x ^{2}\]
\[64+225=x ^{2}\]
\[x ^{2}=289\]
\[x=\sqrt{289}\]
\[x=17\]

- anonymous

@mitodoteira
Can you please help with one more?

- anonymous

Okay

- Jhannybean

Aww that's not being a good sport.

- anonymous

The question didn't ask for x, should be 17^2 or 289

##### 1 Attachment

- anonymous

Emily, what is the other question?

- Jhannybean

the length of the missing side would be what @arafatx mentioned.
You can always plug it back in to the pythagorean identity to check your answer.
a^2 +b^2 = c^2
(15)^2 + (8)^2 = (sqrt (289))^2
225 + 64 = 289

- anonymous

is that for the second one?

- Jhannybean

and for that question,you have a 45-45-90 triangle, therefore your proportions are
1:1:1*sqrt(2)
By that i mean both of your base legs are the same and to find the hypotenuse you're going to multiply your base leg * sqrt(2)

- Jhannybean

b1 = 12, b2 = 12, hypotenuse = b1*sqrt(2)

- anonymous

Since

**
**

- anonymous

you guys are giving me 2 different answers. Which is it?

- anonymous

12*sqrt(2) is about equal to 17

- Jhannybean

@mitodoteira
c^2 = a^2 + b^2 take x = 17, c=x
(17)^2 = (12)^2 + (12)^2
289 = 288 nope.

- anonymous

That's because I'm rounding. The actual answer is irrational. If you look at my answer, I gave the answer to a few decimal places as well.

- Jhannybean

whereas we take c = 12sqrt(2)
c^2= a^2 + b^2
(12sqrt(2))^2 = (12)^2 + (12)^2
288 = 288
You DO NOT round when finding lengths.

- anonymous

I gave the true answer, as well as the rounded one in case she needed it for something (I was often asked to give the answer to n decimal places instead of the exact answer).

- Jhannybean

the "true" answer is 12* sqrt(2) according to the 45-45-90 degree triangle.

- anonymous

Yes, it is. I don't see what the problem is.

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