anonymous
  • anonymous
Find the solutions of the inequality. | x - 5 | ≥ 3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1370555322120:dw|
rajee_sam
  • rajee_sam
for any absolute value inequality you have to set it up like this. | x - 5| ≥ 3 you have to rewrite as -3 ≥ (x -5) ≥ 3 -3 +5 ≥ x ≥ 3+ 5 2 ≥ x ≥ 8
anonymous
  • anonymous
okay thank you :)

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More answers

zzr0ck3r
  • zzr0ck3r
how can x be greater than 8 and less than 2? you broke math
zzr0ck3r
  • zzr0ck3r
solve x-5>=3 and x-5<= -3
zzr0ck3r
  • zzr0ck3r
@rajee_sam forgot to flip a inequality i think...
rajee_sam
  • rajee_sam
no I wrote it right
zzr0ck3r
  • zzr0ck3r
then explain how x can be greater than 8 and less than 2
rajee_sam
  • rajee_sam
x-5 <= -3 is same as -3 ≥ x-5
zzr0ck3r
  • zzr0ck3r
read my last comment
zzr0ck3r
  • zzr0ck3r
solve x-5>=3 and x-5<= -3 x>=8 and x<=2 maybe thats what you meant
zzr0ck3r
  • zzr0ck3r
or*
rajee_sam
  • rajee_sam
you apply some values in this region and check your answer, it WILL satisfy your condition |x-5| ≥ 2
rajee_sam
  • rajee_sam
i mean 3*
zzr0ck3r
  • zzr0ck3r
2 ≥ x ≥ 8 you wrote this^^^ this is never true
zzr0ck3r
  • zzr0ck3r
you meant 2>=x or x>=8
zzr0ck3r
  • zzr0ck3r
it cant be both...
rajee_sam
  • rajee_sam
why not?
zzr0ck3r
  • zzr0ck3r
how can a number be less than 2 and greater than 8?
zzr0ck3r
  • zzr0ck3r
name one such number
rajee_sam
  • rajee_sam
2≥ x≥ 8 simply means x can be any value in the region less than or equal to 2 or ≥ 8 . Does it not?
zzr0ck3r
  • zzr0ck3r
im jsut saying that this makes no sense on the real line 2 ≥ x ≥ 8
zzr0ck3r
  • zzr0ck3r
there is no region that contains a number less than 2 and greater than 8.......
zzr0ck3r
  • zzr0ck3r
x can either be less than 2 or greater than 8 not both
rajee_sam
  • rajee_sam
|dw:1370556304019:dw|
zzr0ck3r
  • zzr0ck3r
yes and that is (-infinity,2]U[8,infinity) not 2>=x>=8
rajee_sam
  • rajee_sam
I am just writing that as a compound inequality
zzr0ck3r
  • zzr0ck3r
put a number where x is 2>=x>=8
rajee_sam
  • rajee_sam
Your (-infinity, 2] U [8, infinity) is the interval notation
zzr0ck3r
  • zzr0ck3r
again tell me one number that satisfies 2>=x>=8 and ill shutup
zzr0ck3r
  • zzr0ck3r
set notation {x|x<=2 or x>=8} this is what you want not the same as {x|2>=x>=8}
rajee_sam
  • rajee_sam
This is way of writing a compound inequality which actually means x can take values less than equal to 2 or ≥ 8. That is all.
zzr0ck3r
  • zzr0ck3r
no its not.. that is no an true inequality, by transitivity that implies 2>=8
zzr0ck3r
  • zzr0ck3r
again just one number and replace x with that number and tell me 2>=x>=8
zzr0ck3r
  • zzr0ck3r
can you tell the difference between {x|x<=2 or x>=8} and {x|2>=x>=8}?
rajee_sam
  • rajee_sam
Ok I get what you are saying
zzr0ck3r
  • zzr0ck3r
{x|2>=x>=8} = {x|x<=2 and x>=8}
rajee_sam
  • rajee_sam
For greater than inequalities I have to split them up otherwise
rajee_sam
  • rajee_sam
I will remember that
zzr0ck3r
  • zzr0ck3r
good deal:)
rajee_sam
  • rajee_sam
Thank you

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