anonymous
  • anonymous
MATH HELP PLEASE STUDY GUIDE ? A helix is a three-dimensional spiral. The coiled strands of DNA and the edges of twisted crepe paper are examples of helixes. In the diagram, the y-coordinate of each edge illustrates a cosine function. Write an equation for the y-coordinate of one edge.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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GoldPhenoix
  • GoldPhenoix
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
what's the amplitude

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anonymous
  • anonymous
@jim_thompson5910 8.5??
jim_thompson5910
  • jim_thompson5910
what's the center line
jim_thompson5910
  • jim_thompson5910
the distance from the center line (which is horizontal) to the peak is the amplitude
anonymous
  • anonymous
@jim_thompson5910 i don't know how to find it..:/
jim_thompson5910
  • jim_thompson5910
the center line is on top of the x axis, see it?
anonymous
  • anonymous
@jim_thompson5910 yeah i do.. would the center line be 0? because it's between 1 an d-1.
jim_thompson5910
  • jim_thompson5910
y = 0 is the center line, yep the distance from the center line to the peak is 1 unit
jim_thompson5910
  • jim_thompson5910
so the amplitude is 1
jim_thompson5910
  • jim_thompson5910
what's the period?
anonymous
  • anonymous
@jim_thompson5910 12?
jim_thompson5910
  • jim_thompson5910
start at (0,1) and follow the path of the curve
jim_thompson5910
  • jim_thompson5910
when do you reach back up to y = 1 again?
anonymous
  • anonymous
@jim_thompson5910 12 because the cycle starts again at the 12 mark??
jim_thompson5910
  • jim_thompson5910
I think at 12, the cycle is at its lowest point
anonymous
  • anonymous
@jim_thompson5910 it's at its highest point at 1?? when it starts off.
jim_thompson5910
  • jim_thompson5910
yes that's true
anonymous
  • anonymous
@jim_thompson5910 so would that be the period?
jim_thompson5910
  • jim_thompson5910
I think it's doing this |dw:1370565560069:dw|
jim_thompson5910
  • jim_thompson5910
that's just one edge of the double helix
anonymous
  • anonymous
@jim_thompson5910 okay.. i see. so the period would be 24??
jim_thompson5910
  • jim_thompson5910
yes I think so
jim_thompson5910
  • jim_thompson5910
now use this info to find the equation
anonymous
  • anonymous
@jim_thompson5910 okay, cool. okay so the general cosine thing is y=A*cos(bx)+d and a is amplitude and b is used to find the cycle length and d is center line.
jim_thompson5910
  • jim_thompson5910
correct
jim_thompson5910
  • jim_thompson5910
glad you wrote that down
jim_thompson5910
  • jim_thompson5910
so A = 1 B = yet to be determined D = 0
jim_thompson5910
  • jim_thompson5910
to find B, you need to evaluate B = 2pi/T where T is the period (in this case T = 24)
anonymous
  • anonymous
@jim_thompson5910 i got 0.26
jim_thompson5910
  • jim_thompson5910
B = 2pi/T B = 2pi/24 B = pi/12
jim_thompson5910
  • jim_thompson5910
I would keep it as a fraction like that
anonymous
  • anonymous
@jim_thompson5910 so b would be b=pi/12?
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
@jim_thompson5910 okay so what do i do next?
jim_thompson5910
  • jim_thompson5910
you have enough info to construct the equation
anonymous
  • anonymous
@jim_thompson5910 okay so would it be y= 1 * cos (pi/12x) + 0??
jim_thompson5910
  • jim_thompson5910
yep, or just \[\large y = \cos\left(\frac{\pi}{12}x\right)\] after you do a bit of simplification
anonymous
  • anonymous
@jim_thompson5910 okay so that would be the answer??
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
@jim_thompson5910 thank you so much for helping :)
jim_thompson5910
  • jim_thompson5910
sure thing

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