Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

neongreenstring

  • 2 years ago

I am having difficulty finding the correct solution to problem 1E-4 part a). The approach should be very similar to that of 1D-7, looking at the answer I do not understand the approach they use and why they use it.

  • This Question is Open
  1. creeksider
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    We need to find values of a and b such that (1) the two expressions have the same value at x=0, and (2) the two expressions have the same derivative at x=0. The first part is so easy that it may be hard to recognize as a solution: when evaluated at x=0, everything drops out of both expressions except the constant 4. Therefore these expressions will always join up at point (0,4) no matter what values we use for a and b. The second part isn't much harder. We need to make the derivatives of the two expressions match up, so we want \[2ax+b=25x^{4}+12x ^{3}+14x+8\] But remember, this is happening at x=0, so everything disappears except b=8. So the final answer is that the function is differentiable when b=8. It doesn't matter what value we choose for a because at x=0 the elements including a disappear in both f(x) and f'(x).

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy