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use y - y1 = m(x - x1) m= 3, point(12,1) y - 1 = 3(x - 12) y - 1 = 3x - 36 y = 3x - 35
write out line equation y=mx+b if it passed thru point (12,1) this means this point is a solution to this line equation so for b where this point is infact a solution to this equation
You have a slope and you have a point...use the point slope formula y - y1 = m(x - x1) replace 'm' with 3...y1 with your y-value and x1 with your x-value y - 1 = 3(x - 12) y - 1 = 3x - 36 y = 3x - 35
lmao wth is all that dan? xD @johnweldon1993 wooo! copying my post? HMMMM? lol jk
u need to understand the principle of what a line is!! everypoint on the line is a solution to the equation of a line, that is how this line is generated
@Jhannybean beat me to that one -_- haha
Well, let's use the form of an equation y=mx+b. We're already given m, so all we need to do is plug in, giving us 1=3(12)+b Solve, giving b=-35 and our final equation of y=3x-35
lmao LISTEN CAREFULLY tpenn!!
haha yeah I saw that for the second I was posted and was like O.o woh ...he's not kidding xD
it* was posted
T-pain u there dog?
learn math and get that bling BLING
-_- @Jhannybean there! haha
i remember you john
yeah from that wonderful "proportional area" question! haha fun times :D haha
yes u hae a good memory
do you like to program?
I enjoy it to a point haha...mainly java and c++ but really just self taught...besides a java class during 1st year