anonymous
  • anonymous
A piece of art is in the shape of an equilateral triangle with sides of 6m. Find the area of the piece of art.
Mathematics
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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johnweldon1993
  • johnweldon1993
you know the area of a triangle is \[\frac{ 1 }{ 2 } b h\] |dw:1370581830579:dw| as you can see...you have 2 right triangles the hypotenuse is 6...and the bottom side is 6/2 = 3 so now you have 1 side...the hypotenuse...find the other side *which will be your height* using the Pythagorean theorem 3² + b² = 6²
anonymous
  • anonymous
thats the answer?
johnweldon1993
  • johnweldon1993
no ..what you get from b = √(6² - 3²) will be your height Then you plug THAT into that other equation along with the base length (6) \[\frac{ 1 }{ 2 } (6) (height)\]

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anonymous
  • anonymous
I lost my calc...:(
johnweldon1993
  • johnweldon1993
well lets see 36 - 9 = 27 √ 27 = 5.19615242270 that is your height \[\frac{ 1 }{ 2 } (6) (5.19615242270)\] and that comes out to 15.59 would be the area
anonymous
  • anonymous
thanks :)
johnweldon1993
  • johnweldon1993
anytime :)
anonymous
  • anonymous
Do go to CA?
anonymous
  • anonymous
@johnweldon1993
johnweldon1993
  • johnweldon1993
No I do not sorry, I'm actually in University :)

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