quadratic formula help? x² + 3 = –4x
i need to know how to solve this using the quadratic formula and i don't understand how to do it

- anonymous

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- zzr0ck3r

do you know the formula?

- zzr0ck3r

a = 1
b = 4
c = 3

- zzr0ck3r

plug and play

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## More answers

- anonymous

what is the formula for it though? like i know i need to plug those numbers in now but i don't remember what formula to plug it into i guess

- anonymous

|dw:1370590288111:dw|

- zzr0ck3r

\[\frac{b^{2}-\sqrt(b^{2}-4ac)}{2a}\]

- zzr0ck3r

c is 4

- zzr0ck3r

not -4

- anonymous

can you show me how to do that please ?

- anonymous

|dw:1370590447947:dw|

- zzr0ck3r

um ignore what that dude did
x² + 3 = –4x
implies
x² +4x+ 3 = 0
so a = 1 b = 4 c = 3
so
\[\frac{-4+\sqrt(4^2-4*1*3)}{2a}\]

- zzr0ck3r

then do the say thing but -4- on top

- anonymous

No ignore what zz said he's an idiot follow what I said

- zzr0ck3r

dude how is b = 3? b is the x term @FutureMathProfessor

- zzr0ck3r

you can apologize when your ready

- anonymous

why did you change your answer lmao i copied it from you

- zzr0ck3r

no need to call names either, don't be mad at me for calling you out for lying about a class you took...lol

- zzr0ck3r

I erased nothing...

- zzr0ck3r

stop trying to be fast, and focus.

- zzr0ck3r

we all know how to complete a square, he asked to show it using the formula...

- zzr0ck3r

@galaxyniall do you see what I did?

- zzr0ck3r

remove the a from the bottom, that was an accident.

- anonymous

what class did i not take? i'm a beast

- anonymous

so i got -3 when i did the equation
but my choices are
1, 3
-1, -3
1, -3
-1, 3

- zzr0ck3r

advanced calculus or abstract algebra

- anonymous

i've taken boath

- zzr0ck3r

prove limit of 1/x

- zzr0ck3r

define a group

- anonymous

which proof do you want me to follow?

- zzr0ck3r

and don't google.

- zzr0ck3r

start typing now...

- zzr0ck3r

there is only one way to prove a limit (see this just tells me you have not taken it).

- zzr0ck3r

ahh off to google...

- anonymous

(-1, -3)

- anonymous

@mayankdevnani ?

- anonymous

Should I tell you what my teacher told me what a group was or what my textbook tells me a group is? They are 2 different thinsg..

- zzr0ck3r

lol,

- zzr0ck3r

ok....

- zzr0ck3r

lol its the exact same thing @mayankdevnani

- zzr0ck3r

you moved 2a over....

- anonymous

owned

- anonymous

@cristina17 but i got -3 when i solved it? wouldn't those make positive 3 i thought for them to be the answer they had to multiply to whatever i got?? i'm confused
@mayankdevnani i already used zz's

- zzr0ck3r

then subtracted b
its actually easier to do it with the formula, because x is alone....

- anonymous

Factor

- anonymous

@FutureMathProfessor factor what? -3?

- anonymous

|dw:1370591083214:dw|

- zzr0ck3r

again he asked to use the quadratic equation, this is not that...

- zzr0ck3r

@galaxyniall what do you not get about what I told you?

- anonymous

I don't think he cares anymore

- zzr0ck3r

lol

- anonymous

@zzr0ck3r i got -3 when i solved it and i don't understand how you break that into two numbers or whatever because all of my answers have 2 numbers

- anonymous

BTW I fanned you, so I got you on speed dial now! And I know when you are online ^_^

- anonymous

@galaxyniall I showed you how to factor and you got -1 and -3

- zzr0ck3r

ahh ok
read the line after that
now do the same thing
but this time its -4-sqrt(...)

- zzr0ck3r

not -4+sqrt(..)

- zzr0ck3r

just change that + to a - and do the same thing

- anonymous

ohhh okay thank you

- zzr0ck3r

np

- anonymous

(-4 +- 2)/2 which when you use the + symbol you will get -3 and when you use the - symbol you will get -1, so your solutions are -1 and -3!

- anonymous

alright ty

- zzr0ck3r

SWEET!

- anonymous

Nice work : Galaxy! You are so smart!

- zzr0ck3r

your picture looks like your frustrated with math

- anonymous

haha yeah lol

- zzr0ck3r

don't be mean, I could easily stump you...and you me.

- zzr0ck3r

sorry for our tirades, its late and we like to mess with each other. Prob not the best place to do it.

- anonymous

It's almost 4am here at Harvard and I'm having too much fun!

- anonymous

it's alright lol it was kinda entertaining so

- anonymous

x^2+3=-4x
x^2+4x+3=0\[(-b(+ or -) \sqrt{b^2 -4ac})/2a\]
so \[-4(+/-)\sqrt{?4-4(1)(3)} = -4(+/-)\sqrt{16-12} = -4(+/-)2 = -4+2 and -4 - 2 you get -2 and -6 then you divide both by 2 and get -1 and -3\]

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