anonymous
  • anonymous
quadratic formula help? x² + 3 = –4x i need to know how to solve this using the quadratic formula and i don't understand how to do it
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
zzr0ck3r
  • zzr0ck3r
do you know the formula?
zzr0ck3r
  • zzr0ck3r
a = 1 b = 4 c = 3
zzr0ck3r
  • zzr0ck3r
plug and play

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anonymous
  • anonymous
what is the formula for it though? like i know i need to plug those numbers in now but i don't remember what formula to plug it into i guess
anonymous
  • anonymous
|dw:1370590288111:dw|
zzr0ck3r
  • zzr0ck3r
\[\frac{b^{2}-\sqrt(b^{2}-4ac)}{2a}\]
zzr0ck3r
  • zzr0ck3r
c is 4
zzr0ck3r
  • zzr0ck3r
not -4
anonymous
  • anonymous
can you show me how to do that please ?
anonymous
  • anonymous
|dw:1370590447947:dw|
zzr0ck3r
  • zzr0ck3r
um ignore what that dude did x² + 3 = –4x implies x² +4x+ 3 = 0 so a = 1 b = 4 c = 3 so \[\frac{-4+\sqrt(4^2-4*1*3)}{2a}\]
zzr0ck3r
  • zzr0ck3r
then do the say thing but -4- on top
anonymous
  • anonymous
No ignore what zz said he's an idiot follow what I said
zzr0ck3r
  • zzr0ck3r
dude how is b = 3? b is the x term @FutureMathProfessor
zzr0ck3r
  • zzr0ck3r
you can apologize when your ready
anonymous
  • anonymous
why did you change your answer lmao i copied it from you
zzr0ck3r
  • zzr0ck3r
no need to call names either, don't be mad at me for calling you out for lying about a class you took...lol
zzr0ck3r
  • zzr0ck3r
I erased nothing...
zzr0ck3r
  • zzr0ck3r
stop trying to be fast, and focus.
zzr0ck3r
  • zzr0ck3r
we all know how to complete a square, he asked to show it using the formula...
zzr0ck3r
  • zzr0ck3r
@galaxyniall do you see what I did?
zzr0ck3r
  • zzr0ck3r
remove the a from the bottom, that was an accident.
anonymous
  • anonymous
what class did i not take? i'm a beast
anonymous
  • anonymous
so i got -3 when i did the equation but my choices are 1, 3 -1, -3 1, -3 -1, 3
zzr0ck3r
  • zzr0ck3r
advanced calculus or abstract algebra
anonymous
  • anonymous
i've taken boath
zzr0ck3r
  • zzr0ck3r
prove limit of 1/x
zzr0ck3r
  • zzr0ck3r
define a group
anonymous
  • anonymous
which proof do you want me to follow?
zzr0ck3r
  • zzr0ck3r
and don't google.
zzr0ck3r
  • zzr0ck3r
start typing now...
zzr0ck3r
  • zzr0ck3r
there is only one way to prove a limit (see this just tells me you have not taken it).
zzr0ck3r
  • zzr0ck3r
ahh off to google...
anonymous
  • anonymous
(-1, -3)
anonymous
  • anonymous
@mayankdevnani ?
anonymous
  • anonymous
Should I tell you what my teacher told me what a group was or what my textbook tells me a group is? They are 2 different thinsg..
zzr0ck3r
  • zzr0ck3r
lol,
zzr0ck3r
  • zzr0ck3r
ok....
zzr0ck3r
  • zzr0ck3r
lol its the exact same thing @mayankdevnani
zzr0ck3r
  • zzr0ck3r
you moved 2a over....
anonymous
  • anonymous
owned
anonymous
  • anonymous
@cristina17 but i got -3 when i solved it? wouldn't those make positive 3 i thought for them to be the answer they had to multiply to whatever i got?? i'm confused @mayankdevnani i already used zz's
zzr0ck3r
  • zzr0ck3r
then subtracted b its actually easier to do it with the formula, because x is alone....
anonymous
  • anonymous
Factor
anonymous
  • anonymous
@FutureMathProfessor factor what? -3?
anonymous
  • anonymous
|dw:1370591083214:dw|
zzr0ck3r
  • zzr0ck3r
again he asked to use the quadratic equation, this is not that...
zzr0ck3r
  • zzr0ck3r
@galaxyniall what do you not get about what I told you?
anonymous
  • anonymous
I don't think he cares anymore
zzr0ck3r
  • zzr0ck3r
lol
anonymous
  • anonymous
@zzr0ck3r i got -3 when i solved it and i don't understand how you break that into two numbers or whatever because all of my answers have 2 numbers
anonymous
  • anonymous
BTW I fanned you, so I got you on speed dial now! And I know when you are online ^_^
anonymous
  • anonymous
@galaxyniall I showed you how to factor and you got -1 and -3
zzr0ck3r
  • zzr0ck3r
ahh ok read the line after that now do the same thing but this time its -4-sqrt(...)
zzr0ck3r
  • zzr0ck3r
not -4+sqrt(..)
zzr0ck3r
  • zzr0ck3r
just change that + to a - and do the same thing
anonymous
  • anonymous
ohhh okay thank you
zzr0ck3r
  • zzr0ck3r
np
anonymous
  • anonymous
(-4 +- 2)/2 which when you use the + symbol you will get -3 and when you use the - symbol you will get -1, so your solutions are -1 and -3!
anonymous
  • anonymous
alright ty
zzr0ck3r
  • zzr0ck3r
SWEET!
anonymous
  • anonymous
Nice work : Galaxy! You are so smart!
zzr0ck3r
  • zzr0ck3r
your picture looks like your frustrated with math
anonymous
  • anonymous
haha yeah lol
zzr0ck3r
  • zzr0ck3r
don't be mean, I could easily stump you...and you me.
zzr0ck3r
  • zzr0ck3r
sorry for our tirades, its late and we like to mess with each other. Prob not the best place to do it.
anonymous
  • anonymous
It's almost 4am here at Harvard and I'm having too much fun!
anonymous
  • anonymous
it's alright lol it was kinda entertaining so
anonymous
  • anonymous
x^2+3=-4x x^2+4x+3=0\[(-b(+ or -) \sqrt{b^2 -4ac})/2a\] so \[-4(+/-)\sqrt{?4-4(1)(3)} = -4(+/-)\sqrt{16-12} = -4(+/-)2 = -4+2 and -4 - 2 you get -2 and -6 then you divide both by 2 and get -1 and -3\]

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