anonymous
  • anonymous
PLEASEE HELPP!!! A parallel circuit has two 8.0-ohm resistors and a power source of 9.0 volts. If a 12.5-ohm resistor is added to the circuit in parallel, how will the current be affected and what value will it have current will increase 2.97 amps current will increase 0.55 amps current will decrease 2.97 amps cureent will decrease 0.55 amps
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
IrishBoy123
  • IrishBoy123
the 12.5Ohm resistor will have a 9v voltage drop across it. therefore, I = V/R = 9/12.5 = 0.72A will flow through it. total current leaving the battery or cell will be increased to |dw:1370617625941:dw|9/8 + 9/8 + 9/12.5 = 2.97A. i've drawn the circuit just to be clearer.

Looking for something else?

Not the answer you are looking for? Search for more explanations.