anonymous
  • anonymous
I'm confused, can anyone explain this?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
If the hypotenuse of a right triangle is 2\[\sqrt{3}\] units long and one of the legs is \[\sqrt{3}\] units long, then how long is the other leg?
anonymous
  • anonymous
Your hypotenuse can be said to be "c" and the legs "a" and "b". c^2 = a^2 + b^2 [2sqrt(3)]^2 = [sqrt(3)]^2 + b^2 b^2 = [2sqrt(3)]^2 - [sqrt(3)]^2
amistre64
  • amistre64
leg^2 + leg^2 = hyp^2

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amistre64
  • amistre64
what part is the confusing part tho?
anonymous
  • anonymous
If you can calculate: [2sqrt(3)]^2 and [sqrt(3)]^2 you should have no problem. Can you do that or do you need further help?
anonymous
  • anonymous
Further hint: (m[sqrt(n)])^2 = (m^2) ([sqrt(n)]^2)
anonymous
  • anonymous
The classic example of this is the 30-60-90 triangle. |dw:1370618928120:dw|
anonymous
  • anonymous
Can you calculate: ([sqrt(n)]^2) ? In words, that means taking the square root of a number and then squaring the result. What do you end up with?
anonymous
  • anonymous
|dw:1370619190445:dw|
anonymous
  • anonymous
@jumboabrfan are you there?
anonymous
  • anonymous
sorry, I'm back. My bad.
anonymous
  • anonymous
Do you see the relationship of "2" and "sqrt(3)" in a 30-60-90 triangle?
anonymous
  • anonymous
Sort of.
anonymous
  • anonymous
The hypotenuse of a 30-60-90 triangle is twice as long as the short side of the triangle, and the long side of the triangle is 1.732 times as long as the short side. 1.732, of course, is: \[\sqrt{3}\]
anonymous
  • anonymous
@amistre64 I'm just trying to figure out how to find the length of the other leg.
anonymous
  • anonymous
@jumboabrfan look at my diagram for your answer.
anonymous
  • anonymous
60-30?
anonymous
  • anonymous
No. How long is the hypotenuse in my drawing?
anonymous
  • anonymous
ohh. 60"
anonymous
  • anonymous
How do you get 60" from 2x???
anonymous
  • anonymous
Oh. I thought you were asking me about the numbers. My bad. Sorry.
anonymous
  • anonymous
Take a breath. Think. The short side of my triangle is x. The long side of my triangle is 1.732x and the hypotenuse is 2x. IF X EQUALS ONE, then: The short side of my triangle = 1 The long side of my triangle = 1.732 The hypotenuse = 2
anonymous
  • anonymous
From: b^2 = [2sqrt(3)]^2 - [sqrt(3)]^2 b^2 = (2^2)(sqrt[3])^2 - [sqrt(3)]^2 b^2 = (4)(3) - 3 = 9 b = sqrt(9) b = 3 a = sqrt(3) c = (2)[sqrt(3)]
anonymous
  • anonymous
@qweqwe123123123123111 Right.
anonymous
  • anonymous
Hmm. My school says the right answer is 3...how can that be though?
anonymous
  • anonymous
That's already been shown. Just read the posts.
anonymous
  • anonymous
If you have a right triangle, and: -The hypotenuse is 2 -another leg is sqrt(3) then the 3rd leg cannot be 3.
anonymous
  • anonymous
@qweqwe123123123123111 , the hypotenuse is not 2, it's 2 times sqrt(3) His problem statement has a continuation line.
anonymous
  • anonymous
Ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhh. I get it now.
anonymous
  • anonymous
Sorry it took me so long to understand. I feel so dumb.
anonymous
  • anonymous
Thanks to both of you for the time y'all took. Sorry about that.
anonymous
  • anonymous
We all get sidetracked at times, np.
anonymous
  • anonymous
uw! Good luck to you in all of your studies and thx for the recognition! @jumboabrfan
anonymous
  • anonymous
@tcarroll010 thanks for the heads up on the length of his hypotenuse. Of course that makes "x" = sqrt(3) (the short leg), and it makes "the other leg" (AKA long leg) sqrt(3)*sqrt(3) which is "3", just like he said... :-) PS, were you getting my PM responses earlier?
anonymous
  • anonymous
You're welcome on the heads up. We all get sidetracked at times. With his continuation of the problem statement, he made it confusing. As long as you got: b = 3 a = sqrt(3) c = (2)[sqrt(3)] which I'm sure you did, you're fine. No, I didn't get your PM's. Maybe they were sent to someone else? @qweqwe123123123123111
anonymous
  • anonymous
@tcarroll010 No, I've been having problems with responding to PMs, and I can't figure out what's going on. I hit the little "reply" arrow, type my response, and click "submit", but all I ever get is that stupid little "wait spinner"; it never finishes sending. So there's quite a few folks running around out there who probably think I'm ignoring them. :-(

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