anonymous
  • anonymous
Which relation does not represent a function? (-8, 4), (-3, 2), (1, 3), (5, -8) (2, 0), (4, 6), (7, 6), (8, 5) (-4, 6), (-1, 1), (0, 4), (4, 7) (1, 2), (2, 5), (5, 7), (1, 3)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
The last one, since the domain numbers are not in order of lowest number to highest. D is the answer.!
zzr0ck3r
  • zzr0ck3r
Look for one where the same x values go to two different y values, this is not a function
zzr0ck3r
  • zzr0ck3r
Domain does not need to be in order....

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zzr0ck3r
  • zzr0ck3r
But the last is the answer
anonymous
  • anonymous
thanks
anonymous
  • anonymous
Yes it does, the sequence has to be in order from the lowest to highest. A, B, and C are, and D isn't since it goes '1, 2, 5, 1' If the 1 at the end was higher than 5, then it would be a function.
zzr0ck3r
  • zzr0ck3r
Because 1 goes to 2 and 1 goes to 3
zzr0ck3r
  • zzr0ck3r
You are very wrong. Sets do not have order. Google it
zzr0ck3r
  • zzr0ck3r
F(1)=2 and f(1)=3 thus it is not a function
anonymous
  • anonymous
Look at the last line in #1, and the third to last line in #2 here ---->http://www.athometuition.com/functions.php
zzr0ck3r
  • zzr0ck3r
PS not all functions increase...
zzr0ck3r
  • zzr0ck3r
The last line says what I said
zzr0ck3r
  • zzr0ck3r
If x=y then f(x) = f(y)
zzr0ck3r
  • zzr0ck3r
We have f(1) =2 and f(1)=3
zzr0ck3r
  • zzr0ck3r
1=1 but f(1) does not equal f(1)
zzr0ck3r
  • zzr0ck3r
Understand?

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