anonymous
  • anonymous
This is discrete functions. Can someone please help?? I can't figure out what I am doing wrong. I am supposed to get the indicated sum, but I keep doing something wrong. This is what series I have to work with x[15] for 0.3+0.003+0.00003+...... I know that a=0.3 and r=0.01 and n=15. so x[n] = a(r^n-1)/r-1 x[n] = 0.3((0.01)^15-1)/0.3-1 x[n] = 0.3((-1))/-7/10 but the outcome is 3/7. Is that the right outcome because the back of my text book says it's 10/33. And I don't understand what I am doing wrong. :/
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
klimenkov
  • klimenkov
What is \(0.01^{15}\)?
anonymous
  • anonymous
that would be the common ratio or "r" to the exponent number of terms or "n"
klimenkov
  • klimenkov
Can you calculate this?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yes, when I calculate it I get 1.E-30, then I subtract 1 and get -1
klimenkov
  • klimenkov
There is a mistake in the denominator. x[n] = 0.3((0.01)^15-1)/0.3-1
anonymous
  • anonymous
oh
anonymous
  • anonymous
wow, I am so clueless
klimenkov
  • klimenkov
Actually, there are two mistakes.
anonymous
  • anonymous
Okay I see where I went wrong. Wow
anonymous
  • anonymous
Thank you so much :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.