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My15girl
 2 years ago
This is discrete functions. Can someone please help?? I can't figure out what I am doing wrong. I am supposed to get the indicated sum, but I keep doing something wrong. This is what series I have to work with x[15] for 0.3+0.003+0.00003+...... I know that a=0.3 and r=0.01 and n=15. so x[n] = a(r^n1)/r1
x[n] = 0.3((0.01)^151)/0.31
x[n] = 0.3((1))/7/10
but the outcome is 3/7. Is that the right outcome because the back of my text book says it's 10/33. And I don't understand what I am doing wrong. :/
My15girl
 2 years ago
This is discrete functions. Can someone please help?? I can't figure out what I am doing wrong. I am supposed to get the indicated sum, but I keep doing something wrong. This is what series I have to work with x[15] for 0.3+0.003+0.00003+...... I know that a=0.3 and r=0.01 and n=15. so x[n] = a(r^n1)/r1 x[n] = 0.3((0.01)^151)/0.31 x[n] = 0.3((1))/7/10 but the outcome is 3/7. Is that the right outcome because the back of my text book says it's 10/33. And I don't understand what I am doing wrong. :/

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klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.2What is \(0.01^{15}\)?

My15girl
 2 years ago
Best ResponseYou've already chosen the best response.0that would be the common ratio or "r" to the exponent number of terms or "n"

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.2Can you calculate this?

My15girl
 2 years ago
Best ResponseYou've already chosen the best response.0Yes, when I calculate it I get 1.E30, then I subtract 1 and get 1

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.2There is a mistake in the denominator. x[n] = 0.3((0.01)^151)/0.31

klimenkov
 2 years ago
Best ResponseYou've already chosen the best response.2Actually, there are two mistakes.

My15girl
 2 years ago
Best ResponseYou've already chosen the best response.0Okay I see where I went wrong. Wow
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