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This is discrete functions. Can someone please help?? I can't figure out what I am doing wrong. I am supposed to get the indicated sum, but I keep doing something wrong. This is what series I have to work with x[15] for 0.3+0.003+0.00003+...... I know that a=0.3 and r=0.01 and n=15. so x[n] = a(r^n1)/r1
x[n] = 0.3((0.01)^151)/0.31
x[n] = 0.3((1))/7/10
but the outcome is 3/7. Is that the right outcome because the back of my text book says it's 10/33. And I don't understand what I am doing wrong. :/
 10 months ago
 10 months ago
This is discrete functions. Can someone please help?? I can't figure out what I am doing wrong. I am supposed to get the indicated sum, but I keep doing something wrong. This is what series I have to work with x[15] for 0.3+0.003+0.00003+...... I know that a=0.3 and r=0.01 and n=15. so x[n] = a(r^n1)/r1 x[n] = 0.3((0.01)^151)/0.31 x[n] = 0.3((1))/7/10 but the outcome is 3/7. Is that the right outcome because the back of my text book says it's 10/33. And I don't understand what I am doing wrong. :/
 10 months ago
 10 months ago

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klimenkovBest ResponseYou've already chosen the best response.2
What is \(0.01^{15}\)?
 10 months ago

My15girlBest ResponseYou've already chosen the best response.0
that would be the common ratio or "r" to the exponent number of terms or "n"
 10 months ago

klimenkovBest ResponseYou've already chosen the best response.2
Can you calculate this?
 10 months ago

My15girlBest ResponseYou've already chosen the best response.0
Yes, when I calculate it I get 1.E30, then I subtract 1 and get 1
 10 months ago

klimenkovBest ResponseYou've already chosen the best response.2
There is a mistake in the denominator. x[n] = 0.3((0.01)^151)/0.31
 10 months ago

My15girlBest ResponseYou've already chosen the best response.0
wow, I am so clueless
 10 months ago

klimenkovBest ResponseYou've already chosen the best response.2
Actually, there are two mistakes.
 10 months ago

My15girlBest ResponseYou've already chosen the best response.0
Okay I see where I went wrong. Wow
 10 months ago

My15girlBest ResponseYou've already chosen the best response.0
Thank you so much :)
 10 months ago
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