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emersonba123
 2 years ago
Determine two pairs of polar coordinates for the point (4,4) with 0° ≤ θ < 360°
emersonba123
 2 years ago
Determine two pairs of polar coordinates for the point (4,4) with 0° ≤ θ < 360°

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FutureMathProfessor
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1370637119764:dw

FutureMathProfessor
 2 years ago
Best ResponseYou've already chosen the best response.1So the radius (r coordinate) is sqrt(32) and the first theta coordinate is 315 degrees. add another 360 to that to get a second theta coordinate, with r constant at sqrt(32)

emersonba123
 2 years ago
Best ResponseYou've already chosen the best response.0You got the sqrt of 32 because r=x^2+y^2. Since it is in the fourth quadrant that's why it is 315 degrees? The answer has to be between 0 and 360 degrees

emersonba123
 2 years ago
Best ResponseYou've already chosen the best response.0I'm not sure how you got 315 degrees

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1@FutureMathProfessor Theta has to be between 0 and 360 degrees so that means there will be one r being positive and one r being negative in another pair of coordinates.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1One pair you found (sqrt(32),315) The other one will have a negative r.

emersonba123
 2 years ago
Best ResponseYou've already chosen the best response.0(4 , 315°), (4 , 135°) is this the answer?

emersonba123
 2 years ago
Best ResponseYou've already chosen the best response.0it shoud say 4sqrt2

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1you can simplify sqrt(32) I'm sure. :) But yes.

emersonba123
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you very much!

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1But your r's are wrong and those pairs you gave.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Oh wait are you saying 4 or 4sqrt2?

emersonba123
 2 years ago
Best ResponseYou've already chosen the best response.04sqrt2 in the coordinate for the r
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