Suppose we are given set A = {1, 2, 3, 4, 6, 12} and a relation, R, from A x A. The relation is defined as follows:
R = {(a, b) | a divides b} where (a, b) are elements of A x A.
a) List all the ordered pairs (a, b) that are elements of the relation.
b) Use the results from part a to construct the corresponding zero-one matrix.

- anonymous

- chestercat

See more answers at brainly.com

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- amistre64

theres 36 of them pairs ..... just cross A with A

- amistre64

got no idea what a 0-1 matrix is tho

- anonymous

If I could get the ordered pairs I can do the matrix that is not hard.
Binary basically

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- amistre64

spose you have 2 sets:
P = p1,p2,p3
Q = q1,q2,q3,q4
PxQ are the ordered pairs (p,q) of all the possible p,q combinations

- anonymous

Okay

- amistre64

A = {1, 2, 3, 4, 6, 12}
AxA
1, 2, 3, 4, 6, 12
1,
2,
3,
4,
6,
12
each row column creates an ordered pair

- zzr0ck3r

(1,1),(1,2),(1,3),(1,4),(1,6),(1,12),(2,2),(2,4),(2,6),(2,12),(3,3),(3,6)......

- anonymous

Okay thanks makes a lot of since thank you as always.

- zzr0ck3r

np

- zzr0ck3r

I don't think there are 36...

- anonymous

so the pair sets would be up to 12,1 and so on right

- amistre64

6x6 = 36

- amistre64

12,12

- zzr0ck3r

(1,1),(1,2),(1,3),(1,4),(1,6),(1,12),(2,2),(2,4),(2,6),(2,12),(3,3),(3,6),(3,12),(4,4),(4,12),(6,6),(6,12),(12,12) sorry your right, I just didn't see it

- amistre64

i might have forgot to read all of it :)
there are 36 ordered pairs of AxA, not all of them will be defined as elements of the Relation :)

- anonymous

That is what I got too.

- anonymous

So that was the easy part
the matrix might be tricky but I will get it figured out
unless someone can figure it out for me.
zzrocker??? get the metal? Professor gets the metal?

- zzr0ck3r

I don't care:) give it to someone else

- zzr0ck3r

hint: @FutureMathProfessor loves metals

- amistre64

im saving up my medals to buy a cheeseburger at mcdonalds

- anonymous

LOLOL

- zzr0ck3r

medal*

- anonymous

I am saving mine for a Bigkids meal at BK

- amistre64

gas is too expensive for me to drive the 15 miles to get to BK :(

- Zarkon

McDonald's is not food :)

- amistre64

lol, most of what i eat is not food so itll fit right in

- Loser66

@FutureMathProfessor shame on you!! medal lover!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.