anonymous
  • anonymous
Another inequality...these bad boys are lethal, need help! Solve the inequality x + 8<5 or -8x<16
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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zzr0ck3r
  • zzr0ck3r
1st equation subtract 8 from both sides 2nd equation divide both sides by -8 and flip the inequality
anonymous
  • anonymous
ok and what would the interval notation look like
zzr0ck3r
  • zzr0ck3r
(-infnity,-3)U(-2,infinity)

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anonymous
  • anonymous
hmm i was sure it was -3,-2 but ight thanks for the help:)
anonymous
  • anonymous
Solve both for \(x\) and *combine.* $$x+8<5\\x+8-8<5-8\\x<-3\\x\in(-\infty,-3)$$and$$-8x<16\\\frac{-8x}{-8}>\frac{16}{-8}\\x>-2\\x\in(-2,\infty)$$hence \(x\in(-\infty,-3)\cap(-2,\infty)=\emptyset\) or, equivalently, \(-2
zzr0ck3r
  • zzr0ck3r
no this is not right
zzr0ck3r
  • zzr0ck3r
or!
zzr0ck3r
  • zzr0ck3r
or not and
zzr0ck3r
  • zzr0ck3r
(-infnity,-3)U(-2,infinity) not (-infnity,-3)n(-2,infinity)
zzr0ck3r
  • zzr0ck3r
it just means x needs to satisfy one equation not both @oldrin.bataku
anonymous
  • anonymous
@zzr0ck3r trust me I know that. I misread 'or' as 'and'. It would correctly be \(x\in(-\infty,-3)\cup(-2,\infty)\)
zzr0ck3r
  • zzr0ck3r
right, that's why I told you:) I assume you would know it....

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