anonymous
  • anonymous
dividing powers 7. 14f^7gh^8 divided by 7g^2h^11 8. 2x^12y^4z^10 divdided by 10x^9y^15z^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1370648701135:dw|
anonymous
  • anonymous
how do i cancel out the g's? :)
anonymous
  • anonymous
you'll have 1 g on the bottom remaining. Medal? :)

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More answers

anonymous
  • anonymous
ok thanks but why did you put 9 @ the end of the f's?
anonymous
  • anonymous
that is a G lolol
whpalmer4
  • whpalmer4
\[\frac{1}{g} = g^{-1}\]
anonymous
  • anonymous
haha thanks how do i solve the f's then? /:
whpalmer4
  • whpalmer4
Well, if you have nothing but f's on the top, then you'll have \(f^n\) where \(n\) is the number of f's you've got.
anonymous
  • anonymous
can you guys please do number 8 :(
whpalmer4
  • whpalmer4
Yes, I'm quite sure I can :-)
whpalmer4
  • whpalmer4
I'm sure you can, too! Do you want to work through it together?
anonymous
  • anonymous
yes please and thank you :)
anonymous
  • anonymous
hello?
whpalmer4
  • whpalmer4
Patience, young grasshopper! Do you need a refresher in handling exponents?
anonymous
  • anonymous
sorry i have just never done this before /:
whpalmer4
  • whpalmer4
\[x^1 = x\]\[x^2 = x*x = x^2\]\[x^3=x*x*x = x^3\]\(x^n = x*x*...*x =x^n\) (\(n\) \(x\)'s)
anonymous
  • anonymous
can't i just do 12-9?
whpalmer4
  • whpalmer4
\[x^a*x^b = x^{a+b}\]\[x^3*x^4 =(x*x*x)*(x*x*x*x) = (x*x*x*x*x*x*x) = x^7 =x^{3+4}\] \[(x^a)^b = x^{a*b}\]\[{(x^3)}^2 = (x*x*x)*(x*x*x) = (x*x*x*x*x*x) = x^6 =x^{2*3}\]
whpalmer4
  • whpalmer4
Well, yes, you can, I hadn't gotten there yet, I thought you hadn't done this before?
anonymous
  • anonymous
yes i never done this before but that's all i really knew
anonymous
  • anonymous
is the answer 5x^3y^4z^8???? /:
anonymous
  • anonymous
hello? /:
whpalmer4
  • whpalmer4
Sorry, got called away...
anonymous
  • anonymous
its ok :) thanks for coming back
anonymous
  • anonymous
i already got the answer so can you help me with another question please?
whpalmer4
  • whpalmer4
No, that answer isn't quite right. Let's break it up: \[\frac{2x^{12}y^4z^{10}}{10x^9y^{15}z^2} = \frac{2}{10}*\frac{x^12}{x^9}*\frac{y^4}{y^{15}} *\frac{z^{10}}{z^2} \]
anonymous
  • anonymous
i gave you a medal :)
whpalmer4
  • whpalmer4
Whoops, a typo in my work there: \[\frac{2x^{12}y^4z^{10}}{10x^9y^{15}z^2} = \frac{2}{10}*\frac{x^{12}}{x^9}*\frac{y^4}{y^{15}} *\frac{z^{10}}{z^2}\] Much better. So what does the 2/10 turn into?
whpalmer4
  • whpalmer4
What was your final answer? If it's right, we can do another one maybe even without interruption :-)

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