anonymous
  • anonymous
A man on the fifth floor of a building shouts down to a person on the street. If the angle of elevation from the street to the man in the building is 35° and the man in the building is 40 feet up, about how far away from the building is the person on the street?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
A) 28 feet B) 55 feet C) 56 feet D) 57 feet
anonymous
  • anonymous
|dw:1370656241983:dw|
anonymous
  • anonymous
\[\sin(35)=\frac{40}{x}\iff x=\frac{40}{\sin(35)}\] and a calculator

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anonymous
  • anonymous
...i can't get it.
anonymous
  • anonymous
hmmm i don't get any of those answers...
anonymous
  • anonymous
are you sure those are the right choices?
anonymous
  • anonymous
Here's the picture that is with the question.
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jim_thompson5910
  • jim_thompson5910
you use tangent, not sine
jim_thompson5910
  • jim_thompson5910
tan(35) = 40/x x*tan(35) = 40 x = 40/tan(35) x = ???
anonymous
  • anonymous
D ?
anonymous
  • anonymous
oooh how far is the building from the man, not the two man doh
jim_thompson5910
  • jim_thompson5910
yeah somewhat of a trick question
anonymous
  • anonymous
what @jim_thompson5910 said i should learn to read
jim_thompson5910
  • jim_thompson5910
57 ft is correct
anonymous
  • anonymous
@satellite73 thank you for trying to help! @jim_thompson5910 Thank you for giving the answer!
anonymous
  • anonymous
\[x=\frac{40}{\tan(35)}\] http://www.wolframalpha.com/input/?i=40%2Ftan%2835%29

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