anonymous
  • anonymous
what is the length of side AD? [picture included]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1370657143296:dw|
anonymous
  • anonymous
under the 40○ its D & C
anonymous
  • anonymous
Since the sections of AD and DC look the same size, the measurements would be the same which is 30.

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More answers

anonymous
  • anonymous
it said that was wrong. AD is a little smaller then DC need another picture?
anonymous
  • anonymous
can u do it clearer, maybe screenshot?
anonymous
  • anonymous
|dw:1370657469311:dw|
anonymous
  • anonymous
everything else isthe same
anonymous
  • anonymous
kk im sorry i have to go , bye!
Jhannybean
  • Jhannybean
|dw:1370657514038:dw|
anonymous
  • anonymous
yes like that
bahrom7893
  • bahrom7893
Here, you can use the law of sines, but you need the top part of angle B |dw:1370657943329:dw|
bahrom7893
  • bahrom7893
Just a sec. I need to draw this on paper
bahrom7893
  • bahrom7893
Ah I see it, easier than expected. Gonna keep drawing it.
bahrom7893
  • bahrom7893
|dw:1370658215982:dw|
bahrom7893
  • bahrom7893
60/Sin(140) = AD/Sin(10)
bahrom7893
  • bahrom7893
http://hyperphysics.phy-astr.gsu.edu/hbase/imgmth/lsin.gif
Jhannybean
  • Jhannybean
How did you get.... the angles... 140 and 10 lol.
bahrom7893
  • bahrom7893
|dw:1370658297672:dw|
Jhannybean
  • Jhannybean
oh -_-
bahrom7893
  • bahrom7893
|dw:1370658357853:dw|
bahrom7893
  • bahrom7893
u can solve for AD yourselves, I'm kinda lazy.
Jhannybean
  • Jhannybean
|dw:1370659281159:dw| \[\large \text{law of sines}: \frac{a}{\sin(A)}= \frac{b}{\sin(B)}\]\[\large \frac{d}{\sin(D)}=\frac{b}{\sin(B)}\]\[\large \frac{60}{\sin(140)}=\frac{x}{\sin(10)}\]\[\large x*\sin(140)=60*\sin(10)\]\[\large x (\text{side AD}) = \frac{60\sin(10)}{\sin (140)}\]

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