anonymous
  • anonymous
A certain mountain has an elevation of 19,702 feet. In 1902 the glacier on this peak covered by 10 acres. By 2001 this glacier had melted to only 1 acre. A: Assume that this glacier melted at a constant rate each year. Find this yearly rate? The yearly rate? What is the equation that gives you the acreage of the glacier t years after 1902?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
acres/year = (10-1 acres) / (1902-2001) = -9/99 acres/year = 0.090909... acres/year melted. That is the yearly rate! For the equation, you need a y-value, an x-value, and a slope (m) value. From the problem, x1 = 10 [Acres] and y1 = 0 [t, years since 1901]. The slope, m, was found earlier to be m = 0.090909... The formula for the equation is y-y1 = m(x-x1). Substituting in, A-0=0.091(t-10). Solve for A, and the final equation is...A=0.091t-0.909!

Looking for something else?

Not the answer you are looking for? Search for more explanations.