Jack1
  • Jack1
differential equation help? how do i rearrange this eqn so it can fit the standard form of y' + P(x) y = q(x) i cant seem to isolate the y's
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Jack1
  • Jack1
(1-2x^2-2y) dy/dx = (4x^3 - 4xy)
Jack1
  • Jack1
trying to do : (4x^3 - 4xy) / (1-2x^2-2y) havve 4x^3 / (1-2x^2-2y) - 4xy/ (1-2x^2-2y)
Jack1
  • Jack1
too many y's

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cwrw238
  • cwrw238
i can't see that this is possible perhaps another method is required
Jack1
  • Jack1
is there another way to differentiate without finding integrating factor...?
anonymous
  • anonymous
yeah, i think you need to do Integrating factors since My = Nx
Jack1
  • Jack1
... My = Nx...? and i cant isolate y so i cant get integrating factor...
anonymous
  • anonymous
I may be wrong, but M(x,y) + N(x,y)*y' = 0 So M = 4x^3 - 4xy My = -4x N = (1-2x^2 - 2y) Nx = -4x So there is an exact solution
anonymous
  • anonymous
I'm a little fuzzy on this part, but I believe you do \[Q = \int\limits_{}^{} M dx \] and then \[Q = \int\limits_{}^{} N dy\] and solve for Q. But I may have some of my subscripts backwards. I can try and sort it out if this doesn't make sense.
Jack1
  • Jack1
sorry dude, u lost me at My = -4x...?
anonymous
  • anonymous
dM / dy = My dN/ dx = Nx
Jack1
  • Jack1
ah, cool, back woth u now
anonymous
  • anonymous
If My = Nx, then there is an exact solution
Jack1
  • Jack1
wukk try working through it that way, cheers for that @Xetion
Jack1
  • Jack1
*will try
anonymous
  • anonymous
I got \[x^4 - 2x^2y +y - y^2 =0\]

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