anonymous
  • anonymous
Please help.. If m∠BAC = 55°, what is m∠DBC? 20° 80° 70° 35°
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
have u tried it yet?
anonymous
  • anonymous
Yes but I don't understand it at all.

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anonymous
  • anonymous
ok, in order for evaluate m∠DBC u must find the measure of DC right?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
and u know that BD=180 (half of perimeter)
anonymous
  • anonymous
one question: what is the measure of BC ?
anonymous
  • anonymous
i mean u have m∠BAC = 55° so BC=2*m∠BAC=110, am i right?
anonymous
  • anonymous
Yeaa
anonymous
  • anonymous
what happend? ok ok
anonymous
  • anonymous
so u can evaluate measure of CD now ... because CD and BD sum to 180 :)
anonymous
  • anonymous
*sum up
anonymous
  • anonymous
How do I find what one of those angles are equal?
anonymous
  • anonymous
which angles?
anonymous
  • anonymous
CD or BD
anonymous
  • anonymous
emm...those are not angles actually but the arcs (part of perimeter)
anonymous
  • anonymous
sorry about that, my notations are not suitable
anonymous
  • anonymous
|dw:1370706609250:dw|
anonymous
  • anonymous
I know what an arc is lol
anonymous
  • anonymous
oh ok :)
anonymous
  • anonymous
so i cant get ur question: How do I find what one of those angles are equal? maybe other helpers ??? :)
anonymous
  • anonymous
I'm so frustrated ):
.Sam.
  • .Sam.
|dw:1370706949158:dw|
anonymous
  • anonymous
I need to find the measure of the radius?
.Sam.
  • .Sam.
|dw:1370707047966:dw|
.Sam.
  • .Sam.
I don't think so, still thinking...
.Sam.
  • .Sam.
Ah x is 35
.Sam.
  • .Sam.
|dw:1370707305784:dw|
.Sam.
  • .Sam.
We're applying this |dw:1370707391287:dw| two times
.Sam.
  • .Sam.
The first time is from angle CAB to COB, "O" is the center, so 55 times 2 is 110, then use 180 minus 110 you'll get 70, then apply that method by dividing 2 from 70 to get 35.
anonymous
  • anonymous
Ahh I see
.Sam.
  • .Sam.
mhm
anonymous
  • anonymous
Thank you, Sam (:
.Sam.
  • .Sam.
you're welcome jess :)

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