A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Parallel resonant "tank" circuits are common in radio equipment. But unfortunately there is always resistance that prevents them from being perfect: in every real inductor, the wire that makes up the inductance has some resistance, and there may be leakage in the capacitor that can be modeled as a resistance. Also, the Norton resistance of the system connected to the tank circut looks like a leakage through the capacitor. So a realistic model for a tank circuit is the following: In the space provided below write an algebraic expression in terms of the device parameters for the bandwidth Δω o
 one year ago
Parallel resonant "tank" circuits are common in radio equipment. But unfortunately there is always resistance that prevents them from being perfect: in every real inductor, the wire that makes up the inductance has some resistance, and there may be leakage in the capacitor that can be modeled as a resistance. Also, the Norton resistance of the system connected to the tank circut looks like a leakage through the capacitor. So a realistic model for a tank circuit is the following: In the space provided below write an algebraic expression in terms of the device parameters for the bandwidth Δω o

This Question is Open

KenLJW
 one year ago
Best ResponseYou've already chosen the best response.1s = jx : x = 2 pi f parallel RLC Tank 1) Z = RsL1/SC = (1/C) s/(s^2 + s/RC + 1/LC) Z^2 = (1/C^2) x^2/(x^2/(RC)^2 + (1/LC x^2)^2) x^2 = 1/LC then Z = R for 3dB points Z^2 =R^2/2 Z^2 = x^2/(x^2 + (RC(1/LC  x^2)^2 =1/2 The two solutions above are the 3dB frequencies, there difference is the BW parallel LC tank with Rs in series with L 2) Z = (sL + Rs)1/sC = (1/C)(s + Rs/L)/(s^2 + sRs/L1/LC) to make the denominator of eq 1 and 2 equal Rs/L = 1/RC R = L/CRs Q = xo L/Rs = 1/xo C Rs R = (xoL/Rs)(1/xoCRs)Rs = RsQ^2 place this R into equation 1 and find lower 3dB frequency and if it's greater than 10 Rs/L then eq 1 and 2 are a good approximation of each other Generally (sL + Rs)1/sC = RpsL1/sC Rp = RsQ^2 for 1/(LC)^1/2 > 10 Rs/L : L/C > 100 Rs^2

KenLJW
 one year ago
Best ResponseYou've already chosen the best response.1correction Lower 3dB point > 10 Rs/L
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.