anonymous
  • anonymous
Solve this quadratic equation. x^2 + 2x - 22 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
What we have to do in this? :/
anonymous
  • anonymous
I mean solve it by quadratic formula?
anonymous
  • anonymous
I believe so?

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anonymous
  • anonymous
The answer is x= -1 plus/minus sqrt(23)
anonymous
  • anonymous
I just need to know how to get there.
anonymous
  • anonymous
LOL @Euler271 explained you na try to do it yourself :P
anonymous
  • anonymous
\[x_{1,2} = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\] for the equation in the form ax^2 + bx + c
anonymous
  • anonymous
in the form ax^2 + bx + c = 0 **
anonymous
  • anonymous
let me know if you want the next step
anonymous
  • anonymous
LOL let him do it xD
anonymous
  • anonymous
46 is what I get.
anonymous
  • anonymous
@tcarroll010 that is confusing :o :/
anonymous
  • anonymous
a = 1; b = 2; c = -22 \[x_{1,2} = \frac{ -2 \pm \sqrt{2^2 - 4(1)(-22)} }{ 2(1) } = \frac{ -2 \pm \sqrt{92} }{ 2 }\]
anonymous
  • anonymous
mmhmm
anonymous
  • anonymous
\[= \frac{ -2 \pm \sqrt{4}\sqrt{23} }{ 2 } = -1 \pm \sqrt{23}\]
anonymous
  • anonymous
@emcrazy14 Where did the sqrt(4) and 23 come from?
anonymous
  • anonymous
@who? lol \[\sqrt{a} \times \sqrt{b} = \sqrt{ab}\]
anonymous
  • anonymous
lol meant @Euler271 anyway, i thought a was 1 and b was 2??
anonymous
  • anonymous
this is in a general case. for any two numbers a and b
anonymous
  • anonymous
ah,
anonymous
  • anonymous
\[\sqrt{92} = \sqrt{4 \times 23} = \sqrt{4} \times \sqrt{23}\]
anonymous
  • anonymous
Ah. Makes sense. Thanks!!!!!!

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