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AJACW22
 2 years ago
Suppose x is normally distributed random variable with μ = 12 and σ =2. Find each of the following probabilities.
a. P (x ≥ 13.5) b. P (x ≤ 8) c. P (12.62 ≤ x ≤ 16.54) d. P (7.02 ≤ x ≤ 15.32)
AJACW22
 2 years ago
Suppose x is normally distributed random variable with μ = 12 and σ =2. Find each of the following probabilities. a. P (x ≥ 13.5) b. P (x ≤ 8) c. P (12.62 ≤ x ≤ 16.54) d. P (7.02 ≤ x ≤ 15.32)

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oldrin.bataku
 2 years ago
Best ResponseYou've already chosen the best response.0They just want you to find Zscores and look up the probabilities in tables. e.g. for the first, find the area to the right of \(Z\) where $$Z=\frac{13.512}2=\frac{1.5}2=0.75$$You can determine the area to the left and subtract from 1.

oldrin.bataku
 2 years ago
Best ResponseYou've already chosen the best response.0(b) just wants the area to the left of \(Z=(812)/2=4/2=2\). Use your table. For (c) and (d), they want the area between two \(Z\):dw:1370722148193:dw

AJACW22
 2 years ago
Best ResponseYou've already chosen the best response.0Oldrin, I don't have a solid background in Algebra or statistics. So i have problems working these problems out. I would not know how to get these anwers to c. and d. without a step by step.

AJACW22
 2 years ago
Best ResponseYou've already chosen the best response.0The answer they have for a and b are 0.227 and 0.023?

oldrin.bataku
 2 years ago
Best ResponseYou've already chosen the best response.0Okay. For (c), first find the appropriate \(Z\) scores:$$Z_1=\frac{12.6212}2=\frac{0.62}2=0.31\\Z_2=\frac{16.5212}2=\frac{4.52}2=2.26$$We want the area between the two. Graphically, you can see this is the difference in their respective lefttails:dw:1370722767214:dw

oldrin.bataku
 2 years ago
Best ResponseYou've already chosen the best response.0So find the areas to the left of \(Z=2.26\) and \(Z=0.31\) in your table. Find their difference.
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