anonymous
  • anonymous
l'hopital rule: lim as t approaches 0 (e^2t-1)/(sin t) ____________________ so when i plug in t as 0, i get 0/0 therefore i can apply l'hopital's rule. once i take the derivative, i get (e^2t)/(cos t). taking the limit to zero, i get 1/1 which equals 1, but the book says 2.
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
No there is a chain rule piece when you apply l'hopital's rule. You will get (2e^(2t))/(cos t). If you take the limit to 0, you get 2
anonymous
  • anonymous
so the derivative of e^x is e^x right? if its e^2x i chain it so it becomes 2e^x?
anonymous
  • anonymous
No, e^(2x) becomes 2e^(2x)

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anonymous
  • anonymous
would you like me to explain why?
anonymous
  • anonymous
yes please
anonymous
  • anonymous
oh nevermind
anonymous
  • anonymous
i got it
anonymous
  • anonymous
thank you so much

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